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marusya05 [52]
3 years ago
15

Solve the inequality for x. 7 > 2x+9

Mathematics
1 answer:
Advocard [28]3 years ago
5 0

Answer:

<h2>x<-1</h2>

Step-by-step explanation:

7 > 2x+9\\\\\mathrm{Switch\:sides}\\\\\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\2x+9-9

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Write each of these as one-place decimals.<br><br> A. 0.30________<br><br> B. 0.90________
qwelly [4]

Answer:

A. 0.3

B. 0.9

By converting these to their tenth form, we can get 1 place decimals

6 0
3 years ago
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Please help me with the answer
gtnhenbr [62]
Answer is D

\frac{4}{x+3}* \frac{x^2+6x+9}{16}=   \frac{1}{(x+3)}* \frac{(x+3)^2}{4}=   \frac{x+3}{4}
7 0
3 years ago
Draw out a two column proof for each problem below. Complete all problems on one page and upload ONE photo of the entire assignm
Hunter-Best [27]

Two or more <u>triangles</u> are <em>congruent </em>if on comparison, they have equal lengths of <u>sides,</u> and measure of <u>angles</u>.

Therefore, the required proofs for each question are shown below:

Problem 1:

<em>Congruent triangles</em> are <u>triangles</u> with equal lengths of <em>corresponding</em> <u>sides</u> and measures of internal <u>angles</u>.

Thus,

                     STATEMENT                          REASON

1. <NMQ ≅ <NPQ                            Any point on a <em>perpendicular bisector</em>      

                                                        makes <u>equal</u> measure of angle with the

                                                        two ends of the<em> line</em> segment.

2. NQ ⊥ MP                                     Definition of a<u> line</u>.

3. MQ ≅ PQ                                     <em>Equal segments</em> of a bisected <u>line</u>.

4. MN ≅ PN                                     Any point on a <em>perpendicular bisector </em>    

                                                        is at the same <u>distance</u> to the

                                                        two ends of the <em>line segment</em>.

5. <MNQ ≅ <PNQ                           <u>Equal</u> measure of the <u>bisected</u> angle.

Problem 2:

A line <em>segment</em> is the shortest <u>distance</u> between two points.

            STATEMENTS                    REASONS

1. m<PSR  ≅ m<PSQ                A <em>perpendicular bisector </em>is always at a right  

                                                  angle to the <u>bisected</u> <em>line segment</em>.

2. m<RPS ≅ m<QPS                 Equal measure of the <u>bisected</u> <em>angle</em>.

3. RS ≅ QS                                Property of a <u>bisected</u> <em>line</em> segment.

4. PR ≅ PQ                                Any point on a <em>perpendicular bisector </em>    

                                                  is at the same <u>distance</u> to the two ends of  

                                                 the <u>line</u> segment.

For more clarifications on the perpendicular bisector of a line segment, visit: brainly.com/question/12475568

#SPJ1

3 0
2 years ago
Does Y+7=2x and<br> 2y=4x-14 have a solution?
Minchanka [31]

Answer: jnj njnjnjknkjkjnkjnkjn

bbnj j

Step-by-step explanation:

7 0
3 years ago
Please help me bro please
GaryK [48]

Answer:

  • n = 11°

⠀

Step-by-step explanation:

  • When two straight lines intersect each other, then the pairs of angles so formed without any common arm are called vertically opposite angles.

  • Vertically opposite angles are equal to each other.

⠀

So,

{\longrightarrow \it\qquad { \ { (6n   - 4) {}^{ \circ}   =  {(5n + 7)}^{ \circ} }}}

⠀

Removing the brackets,

{\longrightarrow \it\qquad { \ { 6n   - 4{}^{ \circ}   =  {5n + 7 \: }^{ \circ} }}}

{\longrightarrow \it\qquad { \ { 6n   - 5n   =  {  7 \: }^{ \circ} +4{}^{ \circ} }}}

{\longrightarrow \it\qquad { \pmb{ n   =  {  11 \: }^{ \circ}  }}}

⠀

Therefore,

  • The value of n is 11°
6 0
3 years ago
Read 2 more answers
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