Answer:
29. 15.87%
30. 4.75%
31. 0.62%
32. probability cannot be calculated (0%)
Step-by-step explanation:
We have that the formula of the normal distribution is:
z = (x - m) / sd
where x is the value we are going to evaluate, m is the mean and sd is the standard deviation
x = 16 and m = 16.5
when sd = 0.5
z = (16 - 16.5) /0.5
z = -1
Now when looking in the z table, we have that the corresponding value is 0.1587, that is, the probability is 15.87%
when sd = 0.3
z = (16 - 16.5) /0.3
z = -1.67
Now when looking in the z table, we have that the corresponding value is 0.0475, that is, the probability is 4.75%
when sd = 0.2
z = (16 - 16.5) /0.2
z = -2.5
Now when looking in the z table, we have that the corresponding value is 0.0062, that is, the probability is 0.62%
when sd = 0
z = (16 - 16.5) / 0
z = infinity
probability cannot be calculated
Answer:
C
because it is given that the vertex is (4, - 1) an an equation C it is clearly seen that the vertex is same.
Answer:
275
Step-by-step explanation:
I don't know if its correct
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
Learn more about computations on:
brainly.com/question/4658834
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
No, this is not true, 22+32 =54 this is not a true statement
