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dangina [55]
3 years ago
7

4 It takes Joaquin hour to hike mile. What is Joaquin’s unit rate, in miles per hour?

Mathematics
2 answers:
torisob [31]3 years ago
4 0
He is walking 1 mile/hour. If it takes him one hour to hike a mile then he is going one mile and hour.

Hope that helps.
erastova [34]3 years ago
4 0
If he walks 1 mile an hour it will take 1 hour to walk a mile 
hope that help and good luck

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An exponential function is expressed in the form y=axb^x. The relation represents a growth when _______ and a decay when ______.
seropon [69]

Answer:

Growth when: b>1.

Decay when: 0<b<1.

Step-by-step explanation:

Any function in the form f(x)=a{\times}b^x , where a > 0, b > 0 and b not equal to 1 is called an exponential function with base b.

If 0 < b < 1 this is an example of an exponential decay.

The general shape of an exponential with b > 1 is an example of exponential growth.

Hence,

An exponential function is expressed in the form f(x)=a{\times}b^x,   The relation represents a growth when  b >1 and a decay when 0<b<1.

5 0
3 years ago
Which ordered pair is a reflection of (3, 7) across the y-axis?
worty [1.4K]

Answer:

(-3, 7)

Step-by-step explanation:

It is like putting a mirror on the y-axis. It is asking what point is the photo negative of the point, like a mirror. You see yourself in the mirror but everything is opposite. Your right hand is your left. So which point is the photo negative of (3, 7)? (-3, 7) Because it is only across the y-axis, the y value stays the same.

3 0
2 years ago
Ellie buys a mobile phone in spain for €352.50. Her brother jack buys an identical phone from japan for ¥39856. Using exchange r
Nonamiya [84]

Answer:

The answer to your question is: Japan

Step-by-step explanation:

Mobile cost in Spain = € 352.5

Mobile cost in Japan = ¥39856

Exchange rate = £1 = €1.41

                           £1 = ¥188

Cost of mobile in pounds

                       £ 1 ------------------ € 1.41

                        x  -----------------   €352.5

                       x = (352.5 x 1) / 1.41

                       x= £250

                      £1   ------------------  ¥188

                      x    ----------------- -¥ 39856

                     x = (39856 x 1) / 188

                     x = £212

Then, it was cheaper in Japan

8 0
3 years ago
Read 2 more answers
Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).
lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted C, which we can parameterize by the vector-valued function,

\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)

for 0\le t\le1, which has differential

\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt

Then with x(t)=y(t)=z(t)=1-t, we have

\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r

=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt

\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)(t^2-2t+2)\,\mathrm dt

Complete the square in the quadratic term of the integrand: t^2-2t+2=(t-1)^2+1=(1-t)^2+1, then in the integral we substitute u=1-t:

\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)((1-t)^2+1)\,\mathrm dt

\displaystyle=-2\int_{u=0}^{u=1}e^{u^2}u(u^2+1)\,\mathrm du

Make another substitution of v=u^2:

\displaystyle=-\int_{v=0}^{v=1}e^v(v+1)\,\mathrm dv

Integrate by parts, taking

r=v+1\implies\mathrm dr=\mathrm dv

\mathrm ds=e^v\,\mathrm dv\implies s=e^v

\displaystyle=-e^v(v+1)\bigg|_{v=0}^{v=1}+\int_{v=0}^{v=1}e^v\,\mathrm dv

\displaystyle=-(2e-1)+(e-1)=-e

So, we have by the fundamental theorem of calculus that

\displaystyle\int_C\nabla f(x,y,z)\cdot\mathrm d\mathbf r=f(1,1,1)-f(0,0,0)

\implies-e=f(1,1,1)-2

\implies f(1,1,1)=2-e

3 0
3 years ago
a student is reading a fictional book at about 300 words per a minute. convert this rate to words per second
Harrizon [31]

300 words divided by 60 seconds would equals 5 words a second

hope this helps

6 0
3 years ago
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