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timurjin [86]
2 years ago
12

Someone please help me find x

Mathematics
2 answers:
a_sh-v [17]2 years ago
4 0
So for a tangent and a secant, you multiply x^2 (since it’s a tangent you square it) and test that equal to 6(6+12) so now you have x^2=6(6+12). solve for X to get sqrt(108) or 10.4

the equation is — tan^2=outside x whole thing

remember to ADD the entire secant (so add 6 plus 12) don’t multiply them (6x12)

x^2=6(6+12)
x^2=6(18) OR x^2=36+72
x^2=108
x=sqrt(108) OR x=10.4
madreJ [45]2 years ago
3 0

Check the picture below.

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Rollie was succesful in losing weight he had a goal weight in mind he went on a diet for three months each month he would lose o
Llana [10]
Let's say that in the beginning he weighted x and at the end he weighted x-y, y being the number of kg he wanted to loose.

first month he lost
y/3

then he lost:  
(y-y/3)/3
this is
(2/3y)/3=2/9y
explanation: ((y-y/3) is what he still needed to loose: y minus what he lost already

and then he lost
 (y-2/9y-1/3y)/3+3 (the +3 is his additional 3 pounts)
 (y-2/9y-1/3y)/3-3=(7/9y-3/9y)/3+3=4/27y+3

it's not just y/3 because each month he lost one third of what the needed to loose at the current time, not in totatl

and  the weight at the end of the 3 months was still x-y+3, 3 pounds over his goal weight!


so:  x -y/3-2/9y-4/27y-3=x-y+3

we can subtract x from both sides:
-y/3-2/9y-4/27y-3=-y+3
add everything up:

-19/27y=-y+6

which means
-19/27y=-y+6

y-6=19/27y

8/27y=6
4/27y=3
y=20.25

so... that's how much he wanted to loose, but he lost 3 less than that, so 23.25

ps. i hope I didn't make a mistake in counting, let me know if i did. In any case you know HOW to solve it now, try to do the calculations yourself to see if they're correct!










5 0
3 years ago
What are the answer to these 5 questions this worth 20 points btw
Sunny_sXe [5.5K]
1. 900 gallons will be burned in 3 hours.

2. 50 gallons of gasoline weighs 300 pounds.

3. 2,124 = 59 yards

4. The person weighs 48 pounds

5. 12 people = 6 tablespoons
8 0
3 years ago
I need help with all these problems and need to know is the ones I did correct
kolezko [41]
Isabelle has a leash for her dog in the backyard. The leash is attached to a post which allows thedog to travel in a circle around the post. The leash is 3 feet long. How much of the yard can thedog reach while on the leash?

5 0
3 years ago
In a flight of 600 km, the speed of the aircraft was slowed down due to bad weather. The average speed of the trip was decreased
UkoKoshka [18]

The average speed would be 600 km/hr.

Step-by-step explanation:

Let the original speed be 'x'

Let the decreased speed be 'x-200'

Distance = 600 km

Time increased by 30 minutes

According to question, it becomes,

\dfrac{600}{x-200}-\dfrac{600}{x}=\dfrac{30}{60}\\\\\dfrac{x-(x-200)}{x^2-200x}=\dfrac{1}{2\times 600}\\\\\dfrac{200}{x^2-200x}=\dfrac{1}{1200}\\\\240000=x^2-200x\\\\x^2-200x-240000=0\\\\x=600,-400

So, The average speed would be 600 km/hr.

5 0
3 years ago
Find the values of sin2u, cos2u, and tan2u given the figure.
Vadim26 [7]

Givens

y = 2

x = 1

z(the hypotenuse) = √(2^2 + 1^2)  = √5

Cos(u) = x value / hypotenuse = 1/√5

Sin(u) = y value / hypotenuse = 2/√5

Solve for sin2u

Sin(2u) = 2*sin(u)*cos(u)

Sin(2u) = 2(\dfrac{1}{\dsqrt{5}} * \frac{2}{\dsqrt{5}} = \dfrac{2}{5}) = 4/5

Solve for cos(2u)

cos(2u) = - sqrt(1 - sin^2(2u))

Cos(2u) = - sqrt(1 - (4/5)^2 )

Cos(2u) = -sqrt(1 - 16/25)

cos(2u) = -sqrt(9/25)

cos(2u) = -3/5

Solve for Tan(2u)

tan(2u) = sin(2u) / cos(2u) = 4/5// - 3/5 = - 0.8/0.6 = - 1.3333 = - 4/3

Notes

One: Notice that you would normally rationalize the denominator, but you don't have to in this case.  The formulas are such that they perform the rationalizations themselves.

Two: Notice the sign on the cos(2u). The sin is plus even though the angle (2u) is in the second quadrant. The cos is different. It is about 126 degrees which would make it a negative root (9/25)

Three: If you are uncomfortable with the  tan, you could do fractions.

\text{tan(2u)} = \dfrac{\dfrac{4}{5}}{\dfrac{-3}{5} } =\dfrac{4}{5} *\dfrac{5}{-3} =\dfrac{4}{-3}

7 0
3 years ago
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