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Tems11 [23]
3 years ago
9

Suppose a line L has an equation Ax + By + C = 0.

Mathematics
1 answer:
kow [346]3 years ago
3 0
B hope this helps _____________---------------------------------------____________

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Hunter-Best [27]

500000 that's the answer
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If someone could please walk me through on how to answer this.
Elis [28]

To isolate c means to separate it completely on one side of the equals sign.


To isolate variables, you apply opposite operations.


In E = mc², m and c are being multiplied together. To separate them, you divide by the variable you want to get rid of. However, you must do this to both sides of the equation always. Whatever you do to one side of the equation you must do to the other side as well. This is so the equation remains true.


Since we want to isolate c, we'll start by dividing both sides by m.


E = mc²

E/m = mc²/m

E/m = c²  --  The m's cancel as 1


Now we have c squared. The opposite of squaring something is taking its square root. Take the square root of each side.


E/m = c²

√(E/m) = √(c²)

√(E/m) = c  --  Opposite operations cancel each other out


And you've isolated c!


Answer:

c = √(E/m)

3 0
3 years ago
Estimate 15% tip on a dinner bill of $59.12 dollars by rounding the first bill amount to the nearest
Serga [27]

Answer:

tenth

Step-by-step explanation:

8 0
3 years ago
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Help me please thank you
Andrews [41]
1st is parallel

2nd is perpendicular

3rd is perpendicular

4th is perpendicular
8 0
3 years ago
Find the equation of the line that passes through (1,3) and is perpendicular to y = 1 − 2 x
egoroff_w [7]

Answer:

y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept.

Perpendicular lines always have slopes that are negative reciprocals (ex. 1/2 and -2, 3/4 and -4/3)

<u>Determine the slope (</u><em><u>m</u></em><u>):</u>

y = 1 -2x

Rearrange into slope-intercept form:

y = -2x+1

Now, we can identify clearly that the slope is -2. Because perpendicular lines always have slopes that are negative reciprocals, a perpendicular line would have a slope of \displaystyle\frac{1}{2}. Plug this into y=mx+b:

y=\displaystyle\frac{1}{2} x+b

<u>Determine the y-intercept (</u><em><u>b</u></em><u>):</u>

y=\displaystyle\frac{1}{2} x+b

Plug in the given point (1,3) and solve for <em>b</em>:

3=\displaystyle\frac{1}{2} *1+b\\\\b=\displaystyle \frac{5}{2}

Therefore, the y-intercept is \displaystyle \frac{5}{2}. Plug this back into y=\displaystyle\frac{1}{2} x+b:

y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}

I hope this helps!

8 0
2 years ago
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