Answer:
all you do is multiply 3.6 and 109 to see if its 45,000 per year
Step-by-step explanation:
Answer:
Ok what's your question? cna you include the graph?
It’s the third dot bc X to the tenth power times y divided by three
Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
S=4P+4Q
S=4(P+Q)
S/4=P+Q
S/4-P=Q
Q=S/4-P
