Answer is 19;
Problem
a1=325 , d=25 , S19=?
Result
S19=10450
Explanation
To find S19 we use formula
Sn=n2⋅(2a1+(n−1)⋅d)
In this example we have a1=325 , d=25 , n=19. After substituting these values into the above equation, we obtain:
Sn19=n2⋅(2a1+(n−1)⋅d)=192⋅(2⋅325+(19−1)⋅25)=192⋅(650+18⋅25)=192⋅(650+450)=192⋅1100=10450
To check all the events (6), we label the chips. Suppose one chip with 1 is labeled R1 and the other B1 (as if they were red and blue). Now, lets take all combinations; for the first chip, we have 4 choices and for the 2nd chip we have 3 remaining choices. Thus there are 12 combinations. Since we dont care about the order, there are only 6 combinations since for example R1, 3 is the same as 3, R1 for us.
The combinations are: (R1, B1), (R1, 3), (R1, 5), (B1, 3), (B1, 5), (3,5)
We have that in 1 out of the 6 events, Miguel wins 2$ and in five out of the 6 events, he loses one. The expected value of this bet is: 1/6*2+5/6*(-1)=-3/6=-0.5$. In general, the expected value of the bet is the sum of taking the probabilities of the outcome multiplied by the outcome; here, there is a 1/6 probability of getting the same 2 chips and so on. On average, Miguel loses half a dollar every time he plays.
C is the answer because i did this and it not that hard if you let the teacher explain to u
A: A is not correct. The two angles mentioned are interior and supplementary. They do not share a common vertex.
B: The two angles that share a common vertex (and are supplementary) are <JKN and <LKN So far this is the answer.
C: <MNP and <JKN are equal so they cannot be adjacent angles. Not when the transversal is on an angle like this.
D: <ONK and <JKN can be shown to be supplementary, but they have no special name. As a result, these two cannot be the answer
Answer:
Explanation:
11 oz / 5 oz, 11 oz : 5 oz, eleven ounces to five ounces
