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olga_2 [115]
3 years ago
15

How many perfect squares are found between 0 and 200

Mathematics
2 answers:
Yuliya22 [10]3 years ago
6 0

1,4,9,16,25,36,49,64,81,100,121,144,169,196

 

topjm [15]3 years ago
4 0

Answer:

14

Step-by-step explanation:

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A manufacturer has cube shaped cardboard boxes with an exact volume of 12000 cubic inches. What is the volum of the largest sphe
vladimir1956 [14]

Answer:

6283 in³

Step-by-step explanation:

The largest sphere that can fit into the cardboard box must have its diameter, d equal to the length, L of the cardboard box.

Since the cardboard box is in the shape of a cube, its volume V = L³

So, L = ∛V

Since V = 12000 in³,

L = ∛(12000 in³)

L= 22.89 in

So, the volume of the sphere, V' = 4πr³/3 where r = radius of cube = L/2

So, V = 4π(L/2)³/3

= 4πL³/8 × 3

= πL³/2 × 3

= πL³/6

= πV/6

= π12000/6

= 2000π

= 6283.19 in³

≅ 6283.2 in³

= 6283 in³ to the nearest whole cubic inch

6 0
3 years ago
Hiiiiiiiiiiiiiiiiiiiiii
rewona [7]

Answer:

Hiiiii

Step-by-step explanation:

4 0
3 years ago
Explain how to do <br> nx$3.25=$325.00
cupoosta [38]
N*3.25=325.00
N=325.00/3.25
N=100
4 0
3 years ago
In the 2004 Olympics, Adam won a gold medal in the men's 500 m kayak race, with a time of 1 min and 37.9 sec. He also won the br
Sedbober [7]

Answer:

The correct answer is Adam rowed faster in the men's 500-meter kayak race.

Step-by-step explanation:

To find the speed he rowed in both races, you need to divide the distance of the race by the time it took him to finish. In the first race, he rowed 500 meters and did it in a time of 1 minute 37.9 seconds, so the speed in that race would be \frac{500}{97.9} or approximately 5.10725 meters per second. In the second race, Adam rowed a distance of 1000 meters and did it in a time of 3 minutes 28.2 seconds, which means his speed in that race would be \frac{1000}{208.2} or approximately 4.80307 meters per second. Since his speed in the first race was faster than his speed in the second race, Adam rowed faster in the first race would be the correct answer.

3 0
3 years ago
solve |5x - 1| &lt; 1 a. {x|0 &lt; x &lt; 2/5} b. {x|x &lt; 0 or x &gt; 2/5} c. {x|-2/5 &lt; x &lt; 2/5}
aliina [53]
<span>|5x - 1| < 1
-1 < 5x - 1 < 1
-1 + 1 < 5x < 1 + 1
0 < 5x < 2
0/5 < x < 2/5
0 < x < 2/5
</span>
8 0
3 years ago
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