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andriy [413]
2 years ago
5

Snow is falling steadily in Syracuse, New York. After 2 hours, 4 inches of snow has fallen. Complete the table. (view picture fo

r table) i just need the answer for the last table. giving brainliest!!

Mathematics
2 answers:
Dima020 [189]2 years ago
6 0

Answer:okk

Step-by-step explanation:

okk

almond37 [142]2 years ago
6 0
Snow inches is double the number of hours
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Tell whether the equation has one, zero, or infinitely many solutions.<br> 5(x – 7) + 5 = 5x – 30
Bezzdna [24]

Answer:

infinite solutions

Step-by-step explanation:

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2 years ago
Rewrite the following equation in slope intercept 7x + 11y = 10
viva [34]
We can do this by subtracting 7x from both sides, getting us:
11y= -7x+10.
We can then divide both sides by 11, giving our final answer:
y = -7/11x+10/11.
Hope this helped!

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3 years ago
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What is 3 divided by 1/5 :(
scZoUnD [109]

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15

Step-by-step explanation:

that's what gogle said

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2 years ago
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Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.
Vera_Pavlovna [14]

Split up the integration interval into 4 subintervals:

\left[0,\dfrac\pi8\right],\left[\dfrac\pi8,\dfrac\pi4\right],\left[\dfrac\pi4,\dfrac{3\pi}8\right],\left[\dfrac{3\pi}8,\dfrac\pi2\right]

The left and right endpoints of the i-th subinterval, respectively, are

\ell_i=\dfrac{i-1}4\left(\dfrac\pi2-0\right)=\dfrac{(i-1)\pi}8

r_i=\dfrac i4\left(\dfrac\pi2-0\right)=\dfrac{i\pi}8

for 1\le i\le4, and the respective midpoints are

m_i=\dfrac{\ell_i+r_i}2=\dfrac{(2i-1)\pi}8

  • Trapezoidal rule

We approximate the (signed) area under the curve over each subinterval by

T_i=\dfrac{f(\ell_i)+f(r_i)}2(\ell_i-r_i)

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4T_i\approx\boxed{3.038078}

  • Midpoint rule

We approximate the area for each subinterval by

M_i=f(m_i)(\ell_i-r_i)

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4M_i\approx\boxed{2.981137}

  • Simpson's rule

We first interpolate the integrand over each subinterval by a quadratic polynomial p_i(x), where

p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx

It so happens that the integral of p_i(x) reduces nicely to the form you're probably more familiar with,

S_i=\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{r_i-\ell_i}6(f(\ell_i)+4f(m_i)+f(r_i))

Then the integral is approximately

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4S_i\approx\boxed{3.000117}

Compare these to the actual value of the integral, 3. I've included plots of the approximations below.

3 0
3 years ago
If y varies directly with x, and y is 12 when x is 8, find y when x is 9.​
jasenka [17]

Answer:

26

Step-by-step explanation:

its not

5 0
2 years ago
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