Answer:
<h2>2.5 hours</h2>
Step-by-step explanation:
Step one:
given data
for train one
speed= 50miles per hour
for train two
speed= 60miles per hour
the total distance between both trains=275miles
Step two:
the expression for speed= distance/time
so that, distance= speed*time
let the time be t
we are going to combine both distances
train one distance =50t
train two distance =60t
Hence total distance
50t+60t=275
110t=1=275
t=275/110
t=2.5 hours
<u>It will take 2.5 hours</u>
Answer:
The magazine that cost $15.24 for 6 issues cost more by $0.60/60 cents.
Step-by-step explanation:
Since $15.24 is 6 issues each and you need to even out the issues add $15.24+$15.24 then you would get $30.48, because its 15.24 each 6 add them both and it would be 12 issues. And the first issue $29.88 for 12 issues is only $29.88 while the other is $30.48 so the one with 6 issues/the second cost more than the first.
60 cents more because 29.88+60=30.48.
QUESTION:- EVALUATE THE EXPRESSION
EXPRESSION:-
![{( \sqrt[6]{27 {a}^{3} {b}^{4} } )}^{2}](https://tex.z-dn.net/?f=%7B%28%20%5Csqrt%5B6%5D%7B27%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B4%7D%20%7D%20%29%7D%5E%7B2%7D%20)
<h3>ANSWER-></h3>
![{( \sqrt[6]{27 {a}^{3} {b}^{4} } )}^{2} \\ {( {27 {a}^{3} {b}^{4} } )}^{ \frac{2}{6} } \\ {({27 {a}^{3} {b}^{4} } )}^{ \frac{ \cancel{2}}{ \cancel6 {}^{ \: 3} } } \\ {(27)}^{ \frac{1}{3} } {a}^{ \frac{3}{3} } {b}^{ \frac{4}{3} } \\{(3)}^{ \frac{ \cancel3}{ \cancel3} } {a}^{ \frac{ \cancel3}{ \cancel3} } {b}^{\frac{3 + 1}{3} } \\3a {b}^{ \frac{ \cancel3}{ \cancel3} } {b}^{ \frac{1}{3} }](https://tex.z-dn.net/?f=%7B%28%20%5Csqrt%5B6%5D%7B27%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B4%7D%20%7D%20%29%7D%5E%7B2%7D%20%20%5C%5C%20%7B%28%20%7B27%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B4%7D%20%7D%20%29%7D%5E%7B%20%5Cfrac%7B2%7D%7B6%7D%20%7D%20%20%5C%5C%20%7B%28%7B27%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B4%7D%20%7D%20%29%7D%5E%7B%20%5Cfrac%7B%20%5Ccancel%7B2%7D%7D%7B%20%5Ccancel6%20%7B%7D%5E%7B%20%5C%3A%20%203%7D%20%7D%20%7D%20%5C%5C%20%7B%2827%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%7Ba%7D%5E%7B%20%5Cfrac%7B3%7D%7B3%7D%20%7D%20%20%7Bb%7D%5E%7B%20%5Cfrac%7B4%7D%7B3%7D%20%7D%20%5C%5C%7B%283%29%7D%5E%7B%20%5Cfrac%7B%20%5Ccancel3%7D%7B%20%5Ccancel3%7D%20%7D%20%20%7Ba%7D%5E%7B%20%5Cfrac%7B%20%5Ccancel3%7D%7B%20%5Ccancel3%7D%20%7D%20%20%7Bb%7D%5E%7B%5Cfrac%7B3%20%2B%201%7D%7B3%7D%20%7D%20%5C%5C3a%20%7Bb%7D%5E%7B%20%5Cfrac%7B%20%5Ccancel3%7D%7B%20%5Ccancel3%7D%20%7D%20%20%7Bb%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20)
![\\ ANSWER->3ab \sqrt[3]{b} \: \: \: \: \: or \: \: 3a {b}^{ \frac{4}{3} }](https://tex.z-dn.net/?f=%20%5C%5C%20ANSWER-%3E3ab%20%5Csqrt%5B3%5D%7Bb%7D%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%5C%3A%203a%20%7Bb%7D%5E%7B%20%5Cfrac%7B4%7D%7B3%7D%20%7D%20)
Answer:I think Jordan is this a trick question
Step-by-step explanation:
