Answer:
We need to find the area of the semicircles + the area of the square.
The area of a square is equal to the square of the lenght of one side.
As = L^2 = 58m^2 = 3,364 m^2
Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:
Ac = pi*(d/2)^2 = 3.14*(58m/2)^2 = 3.14(27m)^2 = 2,289.06m^2
And the area of a semicircle is half of that, so the area of each semicircle is:
a = (2,289.06m^2)/2 = 1,144.53m^2
And we have 4 of those, so the total area of the semicircles is:
4*a = 4* 1,144.53m^2 = 4578.12m^2
Now, we need to add the area of the square 3,364 m^2 + 4578.12m^2 = 7942.12m^2
This is nothing like the provided anwer of Val, so the numbers of val may be wrong.
Answer:
B
Step-by-step explanation:
The end behavior of a function is how the graph behaves as it approaches negative and positive infinity.
Let's take a look at each end.
As x approaches negative infinity:
As x approaches the left towards negative infinity, we can see that the graph is shooting straight upwards.
Therefore, as
, our function f(x) is increasing and increasing up towards positive infinity.
Therefore, the end behavior at the left will be:

As x approaches (positive) infinity:
As x approaches the right towards positive infinity, we can see the that graph is also shooting straight upwards.
Therefore, the end behavior will be exactly the same. As x approaches positive infinity, f(x) <em>also</em> approaches positive infinity.
Therefore, the end behavior at the right will be:

Therefore, our answer is B.
Answer:
B, C, E, F
Step-by-step explanation:
The following relationships apply.
- the diagonals of a parallelogram bisect each other
- the diagonals of a rectangle are congruent
- the diagonals of a rhombus meet at right angles
- a rectangle is a parallelogram
- a parallelogram with congruent adjacent sides is a rhombus
__
CEDF has diagonals that bisect each other, and it has congruent adjacent sides. It is a parallelogram and a rhombus, but not a rectangle. (B and C are true.)
ABCD has congruent diagonals that bisect each other. It is a parallelogram and a rectangle, but not a rhombus. (There is no indication adjacent sides are congruent, or that the diagonals meet at right angles.) (E and F are true.)
The true statements are B, C, E, F.
Answer:
No Possible Triangles
Step-by-step explanation:
Deltamath