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Lostsunrise [7]
2 years ago
8

No link need right answer

Mathematics
1 answer:
solniwko [45]2 years ago
5 0

Answer:

i think its the third one

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Factorise the following.​
zepelin [54]

Answer:

Step-by-step explanation:

i). \frac{48a^3}{6a}=\frac{6\times 8\times a\times a^2}{6a}

          =\frac{6a}{6a}\times 8a^2

          = 8a²

ii). \frac{72a^3b^4c^5}{8ab^2c^3} = \frac{8\times 9\times a\times a^2\times b^2\times b^2\times c^2\times c^3}{8ab^2c^3}

                = \frac{8ab^2c^3}{8ab^2c^3}\times 9a^2b^2c^2

                = 9a²b²c²

8 0
3 years ago
A square window has a perimeter of (8x+12) feet. Write an expression that represents the side length of the window (in feet). Pl
luda_lava [24]
Perimeter of a square = 4L
4L = (8x+12)ft
L= (2x+3)ft
5 0
3 years ago
Given that 1 inch = 2.54 cm enter the value that will complete this expression for converting 3.5 feet to cm
Lerok [7]

Answer:

106.68

Step-by-step explanation:

13.5*12=42

42*2.54=106.68

7 0
3 years ago
Identify the center and the radius of a circle that has a diameter with endpoints at (−5, 9) and (3, 5)
marusya05 [52]

Check the picture below, so the circle looks more or less like that one.

well, the center of it is simply the Midpoint of those two points, and its radius is simply half-the-distance between them.

~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 3 -5}{2}~~~ ,~~~ \cfrac{ 5 + 9}{2} \right)\implies \left( \cfrac{-2}{2}~~,~~\cfrac{14}{2} \right)\implies \stackrel{center}{(-1~~,~~7)} \\\\[-0.35em] ~\dotfill

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[3 - (-5)]^2 + [5 - 9]^2}\implies d=\sqrt{(3+5)^2+(-4)^2} \\\\\\ d=\sqrt{8^2+16}\implies d=\sqrt{80}\implies d=4\sqrt{5}~\hfill \stackrel{\textit{half the diameter}}{\cfrac{4\sqrt{5}}{2}\implies \underset{radius}{2\sqrt{5}}}

8 0
2 years ago
Help, my daughter is learning about finding lengths of unknown sides. I have no idea how to help on these three homework problem
Lyrx [107]
BC = 4
GE= 23
QR = 7
TR = 11
BD = 22
FG = 6

explanation: you have to look at the numbers at the opposite side of where it’s asking, for example the first one; on the opposite side of BC it’s 12 and other side is 8 and you have to find the space in between so to find BC you would have to subtract 12-8 and you’ll get 4
basically a bunch of subtraction and addition, just look at the numbers on the opposite side. hope this helps !
5 0
3 years ago
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