Answer:
17zy
Step-by-step explanation:
big brain
Answer:
a. Class width=4
b.
Class midpoints
46.5
50.5
54.5
58.5
62.5
66.5
70.5
c.
Class boundaries
44.5-48.5
48.5-52.5
52.5-56.5
57.5-60.5
60.5-64.5
64.5-68.5
68.5-72.5
Step-by-step explanation:
There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,
Class
Interval frequency
45-48 1
49-52 3
53-56 5
57-60 11
61-64 7
65-68 7
69-72 1
a)
Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.
Class width=49-45=4
b)
The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.
Class
Interval Midpoints
45-48 
49-52 
53-56 
57-60 
61-64 
65-68 
69-72 
c)
Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.
Class
Interval Class boundary
45-48 44.5-48.5
49-52 48.5-52.5
53-56 52.5-56.5
57-60 56.5-60.5
61-64 60.5-64.5
65-68 64.5-68.5
69-72 68.5-72.5
To find the answer you multiply 257600 by 115% or 1.15 and the Answer you get you subtract from 257600!
So to convert from leiters per minute to milileters per second
lieters=L
milileters=ml
minute=M
second=S
L/M=liters pre minute
ml/s=milileters per second
so to convert, just conver them seperately first
L=1000ml
M=60S
therefor
conversion factor for M to S=
M times 60S/1M=minutes
conversion factor from L to ml=
L times 1000ml/L
so basically to convert, just multiply the equations gotether
L/M times 1000ml/L times M/60s (we flipped the M to S equation since M is on the bottom) =L/M times 1000/60=L/M times 100/6=L/M times 50/3
if you have 50 liters per minute than
50/1 times 50/3=2500/3=833.33333 ml per second
This is a system of equations problem. Set up the 2 equations like so: If the angles are complementary then they add up to 90, therefore, a + b = 90. We also know that a is 16 more than b. The word "is" means equals and "more" is addition. Therefore, a is 16 more than b is "a = b + 16". Now sub in that value of a (b + 16) into the first equation and solve for b. Then back-substitute to solve for a. (b + 16) + b = 90 so 2b + 16 = 90 and 2b = 74. So b = 37. If b = 37, then a + 37 = 90 and a = 53. Check yourself to make sure that 37 + 53 add up to equal 90 (they do, just get used to checking yourself for accuracy).
