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3 years ago

F(x) -x^2 -2x+13 help

Mathematics

2 answers:

Sedaia [141]3 years ago

5 0

-3 hope i helped :) !!!!

melamori03 [73]3 years ago

4 0

Answer:

x =1 or -3

Step-by-step explanation:

10 = -x^2 - 2x + 13

when you solve that equation^ you get your answer to be either 1 or -3. Since -3 is a negative number, I would just type in x = 1

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Circle an expression and the variable you would substitute if for in each system y=2x <br>x+3y=14

Len [333]

X=2

Y=4

Multiply top so y values cancel out, so multiple top by -3. Y values cancel out. You combine top and bottom equations, x=2. Plug 2 in first equation for x. Y=4

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3 years ago

Algebra

vladimir2022 [97]

(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1

-4x - 6y = -24
4x - 3y = 6

You can cancel out the x values by adding the two equations together.
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2

Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3

Check... (x = 3, y = 2)
2(3) + 3(2) = 12
6 + 6 = 12
12 = 12 <- this works!

4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!

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3 years ago

Read 2 more answers

b&b inc. has ordered machine parts and receives a charge of $15 for shipping and handling plus $20 per part. write an equati

larisa [96]

Answer:

C = 15 + 20*p

Step-by-step explanation:

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C = 15 + 20*p

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3 years ago

I need help combining functions!

postnew [5]

$\bf \begin{cases}
f(x)=\cfrac{2}{x}\\\\
g(x)=\cfrac{x}{x+2}
\end{cases}\qquad g[\quad f(x)\quad ]=\cfrac{[f(x)]}{[f(x)]+2}$

$\bf (g\circ f)(x)\iff g[\quad f(x)\quad ]=\cfrac{\boxed{\frac{2}{x}}}{\boxed{\frac{2}{x}}+2}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{\frac{2}{x}}{\frac{2x+2}{x}}\implies g[\quad f(x)\quad ]=\cfrac{2}{x}\cdot \cfrac{x}{2x+2}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{2x}{2x^2+2x}\implies g[\quad f(x)\quad ]=\cfrac{2x}{2x(x+1)}
\\\\\\
g[\quad f(x)\quad ]=\cfrac{1}{x+1}$

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3 years ago

Pls help I will give brainliest

Brut [27]

Answer and Step-by-step explanation: (MAKE ME BRAINLIEST)

Simplified version

1) √14/6

2)√2

3)√7/3

4)√3/7

*step by step is shown in the photos.

4 0

3 years ago