All categories

2 years ago

The slope of the line whose equation is x-3y= 1 is 0-3 -1/3 0 0 1/3

Mathematics

1 answer:

insens350 [35]2 years ago

5 0

x-3y= 1

The equation needs to be rewritten in proper Slope intercept form ( y = mx+b) where m is the slope and b is the y-intercept.

x-3y = 1

Subtract x from each side:

-3y = 1-x

Divide both sides by -3:

y = 1/-3 - x/-3

Simplify:

y = 1/3x - 1/3

The slope is 1/3

You might be interested in

a sum of money is divided among ethan June way and Raj in the ratio of 5:6:9 after eating gave $50 to his mother the ratio becom

Natasha_Volkova [10]

The answer you are looking for is 35

5 0

2 years ago

According to science, Earth is about 4.5 billion years old and written human history extends back about 10,000 years. Suppose yo

zalisa [80]

It begins in 30000 bc

5 0

2 years ago

Read 2 more answers

The formula V=Bh, where B represents the area of the base, can be used to find the volume of a cylinder. Which formula is equiva

Karo-lina-s [1.5K]

Answer:

Explanation:

B=Base Area

In a cylinder, the base area is a circle.

Area Circle=pi r^2

Replace base area with area of circle:

V=pi r^2 H

7 0

2 years ago

Read 2 more answers

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .

The area (in square inches) of the circle that the hexagon did not cover would be:

$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

3 0

2 years ago

What foes the acronym FDA stands for

vlabodo [156]

Food and Drug Administration.

6 0

2 years ago