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user100 [1]
3 years ago
13

Olivia invested $2,400 in an account paying an interest rate of 4.6% compounded continuously. Assuming no deposits or withdrawal

s are made, how long would it take, to the nearest tenth of a year, for the value of the account to reach $3,550?
Mathematics
2 answers:
chubhunter [2.5K]3 years ago
7 0

Answer:

8.7 so either 8 or 9 tenth of a year

Step-by-step explanation:

<em>Is it compounded per month? I assume</em>

1. Compound interest formula

FV = PV(1+r/100k)^kn

FV is the future value,

PV is the present value,

n is the number of years,

k is the number of compounding periods per year

r% is the nominal annual rate of interest

2. Plug in numbers

3550 = 2400(1+4.6/100*12)^12*n

71/48 = (6023/6000)^12n

12n = logBase(6023/6000)*(71/48)

n = answer/12

n ≈ 8.70

FinnZ [79.3K]3 years ago
5 0
8.7 so 8 or 8 of they year is the amount.
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Answer:

y=2x^2-\frac{4}{3}x-\frac{10}{3}

Step-by-step explanation:

we know that

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3 years ago
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2 years ago
NEED HELP ASAP (please and thank you)
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i dont know how to explain. i just did the math. hope this helps.

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