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3 years ago

14

Please help me 8th grade math

1 answer:

mamaluj [8]3 years ago

7 0

Answer:

y=1/2x+6

Step-by-step explanation:

for the equation you start with finding the rate of change (wich is what y changes by as x 9minths) in creases by 1) and then add the Y-intercept, so it would be Y=1/2x+6

Formula:

Y=△y•x+b(y-int)

To find y intercept find what <em>y </em>is when x is 0, or in this case you know it comes out 6 feet tall, so that is what the Y int. is

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I really don’t know how to do this and i could really use some help :) please

Firlakuza [10]

Answer:oh goodness

Step-by-step explanation:

3 0

4 years ago

What's the slope of 4x-5y+20=0

expeople1 [14]

Answer:

Step-by-step explanation:

4

7 0

3 years ago

Standing on a cliff 380 meters above the sea, Pat sees an approaching ship and measures its angle of depression, obtaining 9 deg

exis [7]

Answer:

(a). 2399.23 meters.

(b). 1944.19 meters apart.

Step-by-step explanation:

Please find the attachment.

We have been given that standing on a cliff 380 meters above the sea, Pat sees an approaching ship and measures its angle of depression, obtaining 9 degrees.

(a) We are asked to find how far from the shore is the ship.

We know that tangent relates opposite side of a right triangle with its adjacent side.

$\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}$

$\text{tan}(9^{\circ})=\frac{380}{x}$

$x=\frac{380}{\text{tan}(9^{\circ})}$

$x=\frac{380}{0.158384440325}=2399.22557$

Therefore, the ship is approximately 2399.23 meters away from the shore.

$\text{tan}(5^{\circ})=\frac{380}{x+y}$

$x+y=\frac{380}{\text{tan}(5^{\circ})}$

$x+y=\frac{380}{0.087488663526}$

$2399.22557+y=4343.419875$

$y=4343.419875-2399.22557$

$y=1944.194305\approx 1944.19$

Therefore, the both ships are approximately 1944.19 meters apart.

7 0

3 years ago

What is the positive value of “x”?<br> x(x+5)=387<br> Hint: Use the quadratic formula

nadya68 [22]

Answer:

<h2>x= −5−11√13/2, −5+11√13/2</h2>

Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula.

Exact Form:

x= −5−11√13/2, −5+11√13/2

Decimal Form:

x=17.33053201…,

−22.33053201…

Step-by-step explanation:

x(x+5)=387

Simplify

x(x+5).

x^2+5x=387

Subtract 387 from both sides of the equation.

x^2+5x−387=0

Use the quadratic formula to find the solutions.

−b±√b^2−4(ac)/2a

Substitute the values a=1, b=5, and c= −387 into the quadratic formula and solve for x.−5±√5^2−4⋅(1⋅−387)/2⋅1

Simplify.

x=−5±11√13/2

The final answer is the combination of both solutions.

x=−5−11√13/2, −5+11√13/2

The result can be shown in multiple forms.

Exact Form:

x=−5−11√13/2,−5+11√13/2

Decimal Form:

x=17.33053201…,

−22.33053201…

<h2>Hope it is helpful....</h2>

7 0

3 years ago

Read 2 more answers

Billy jogs 4/5 kilometer every minute.how many kilometers does he jog after 6 1/8 minutes?

Fudgin [204]

Answer:

$Distance =24\frac{1}{2}\ km$

Step-by-step explanation:

Given

$Rate = \frac{4}{5} km/ min$

Required

Determine the distance covered in $6\frac{1}{8}\ min$

The distance is calculated using:

$Distance = Rate * Time$

This gives:

$Distance = 4 * 6\frac{1}{8}$

Convert to improper fraction

$Distance = 4 * \frac{49}{8}$

$Distance = \frac{4 * 49}{8}$

$Distance = \frac{196}{8}$

$Distance =24\frac{1}{2}\ km$

3 0

3 years ago