Answer:
a) gold - Solid
b) gasoline - liquid
c) oxygen - gaseous
d) olive oil - liquid
e) mercury (found in thermometers) - liquid
f) aluminum - solid
Explanation:
Matter exists in three states viz: solid, gas and liquid. Note that, room temperature is a neither hot or cold temperature, which is about 20-23°C.
A) Gold is a transition metal with the symbol Au. At a room temperature, Gold, like most metals are found as SOLIDS.
B) Gasoline is a liquid mixture of refined hydrocarbons majorly used as fuels.
C) Oxygen is a chemical element with symbol O. It is a constituent of natural air, which is a mixture of different gases including oxygen. Hence, at room temperature, Oxygen is a gas.
D) Olive oil is a vegetable oil got from olives. It is composed of fats and it's a liquid at room temperature.
E) Mercury is an element with symbol Hg. It is the only metallic element found naturally (at room temperature) as a liquid. It is used in thermometers.
F) Aluminum is another chemical element with symbol Al. It is a lustrous metal that occurs as a Solid in room temperature.
Answer :By the time thermal equilibrium is attained in the system, ice is completely converted to water.
What is tehrmal equilibrium?
Thermal equilibrium is a situation in which two substances are exactly at the same temperature. That is. Heat is no longer flowing beween the bodies.
Recall that an insulated thermos flask implies that heat does not eneter or leave the system. Heat will flow from the water to the ice untill the both attains the same temperature and the ice is completely converted to water.
Have a good day
Answer:
Pairs of liquids that will mix in all proportions are called a.) miscible liquids. An unsaturated solution has solute less than the maximum.
Explanation:
i hope this helps . MISCIBLE LIQUIDS
(exact weight of isotope #1) (abundance of isotope #1) + (exact weight of isotope #2) (abundance of isotope #2) = average atomic weight of the element(68.72*61.29) + (39.71*70.92) = 4211.84 + 2816.237028.07/100= 70.28
70.28 is the atomic mass of Gallium for the location
Colligative properties calculations are used for this type of problem. Calculations are as follows:
ΔT(boiling point) = 101.02 °C - 100.0 °C= 1.02 °C
<span>ΔT(boiling point) = (Kb)m
</span>m = 1.02 °C / 0.512 °C kg / mol
<span>m = 1.99 mol / kg
</span><span>ΔT(freezing point) = (Kf)m
</span>ΔT(freezing point) = 1.86 °C kg / mol (<span>1.99 mol / kg)
</span>ΔT(freezing point) = 3.70 <span>°C
</span>Tf - T = 3.70 <span>°C
T = -3.70 </span><span>°C</span>
