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viva [34]
4 years ago
8

The boiling point of an aqueous solution is 101.02 °C. What is the freezing point?

Chemistry
1 answer:
kompoz [17]4 years ago
3 0
Colligative properties calculations are used for this type of problem. Calculations are as follows:

ΔT(boiling point) = 101.02 °C - 100.0 °C= 1.02 °C
<span>ΔT(boiling point)  = (Kb)m
</span>m =  1.02 °C / 0.512 °C kg / mol
<span>m = 1.99 mol / kg

</span><span>ΔT(freezing point)  = (Kf)m
</span>ΔT(freezing point)  = 1.86 °C kg / mol (<span>1.99 mol / kg)
</span>ΔT(freezing point)  = 3.70 <span>°C
</span>Tf - T = 3.70 <span>°C
T = -3.70 </span><span>°C</span>
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