Can we get a picture please?
According to Dalton's law of partial pressures, a mixture of gases inflict pressure in a direct proportion to their volume/mass etc. Therefore, since 79 percent of the air is composed of nitrogen and 21 percent of Oxygen, we multiply 101.3 kPa by 0.79 = 80.027 kPa by Nitrogen, 101.3 kPa by 0.21 = 21.273 kPa by Oxygen.
Answer:
Removing the worms is they first key to overcoming this problem. Thus you should ensure that the worms have not spread throughout the house/facility, or caused more damage.
Secondly, you should replace the pipes taht the worms got into, or clean them at most. If it’s simply worm droppings then just clean it, but if it’s more and worse than that alike slime then it is best to remove and replace it.
the only way the worms escaping could affect something is if they decontaminated it, or alas ate or destroyed it. Other than that if they died you could simply replace them, but e things cannot be replaced
Explanation:
You didn’t actually tell us any details so that the best I got from that
can I have brainlest pwease?
Chemical formula of the glucose: C₆H₁₂O₆
We calculate the molar mass:
atomic mass (C)=12 u
atomic mass (H)=1 u
atomic mass (O)=16 u
atomic weight (C₆H₁₂O₆)=6(12 u)+12(1u)+6(16 u)=72 u+12u+96 u=180 u.
Therefore : 1 mol of glucose will be 180 g
The molar mass would be: 180 g/ mol
2) we calculate the number of moles of 1.5 g.
180 g---------------------1 mol
1.5 g---------------------- x
x=(1.5 g * 1 mol) / 180 g≈8.33*10⁻³ moles
we knows that:
1 mol = 6.022 * 10²³ particles (atoms or molecules)
3)We calculate the number of molecules:
Therefore:
1 mol-----------------------6.022*10²³ molecules of glucose
8.33*10⁻³ moles-------- x
x=(8.33*10⁻³ moles * 6.022*10²³ molecules)/1 mol≈5.0183*10²¹ molecules.
4)We calculate the number of C, H and O atoms:
A molecule of glucose have 6 atoms of C, 12 atoms of H, and 6 atoms of O,
number of atoms of C=(6 atoms/1 molecule)(5.0183*10²¹molecules)≈
3.011*10²²
number of atoms of H=(12 atoms/1 molecule)(5.0183*10²¹ molecules)≈
6.022*10²² .
number of atoms of O=(6 atoms/1 molecule)(5.0183*10²¹ molecules)≈
3.011*10²²
Answer: we have 3.011*10²² atoms of C, 6.022*10²² atoms of H, and 3.011*10²² atoms of O.
