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snow_lady [41]
3 years ago
7

Show You Know It: Mole Relationships

Chemistry
1 answer:
natulia [17]3 years ago
8 0

Answer:

1.785 mol

Explanation:

Divide 159 by 89.1 to get moles.

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Convert 0.30 m to mm.
scoundrel [369]

Answer:

0.3 Meters = 300 Millimeters

Explanation:

Multiply the length value by 1000

Hopefully, this helps! :D

7 0
3 years ago
Find the empirical formula of the following compounds:<br> (c) A hydrocarbon with 79.9 mass % carbon
rodikova [14]

The compound is 82.76% C and 17.24% H

In chemistry, the empirical formula of a chemical compound is the simplest whole number ratio of atoms present in a compound.

<h3>Describe the empirical formula.</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea.

The simplest whole number ratio of each type of atom in a compound is its empirical formula. It can be determined from data on the mass of each component in a compound or from the composition's proportion.

To learn more about chemical reaction visit:

brainly.com/question/14044066

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8 0
2 years ago
Neon in a piston is compressed to a volume of 14L its original volume was 22 L at 11.2 atm find the new pressure in atm
Jobisdone [24]
I love chem!!! Hopefully I got it right for u I got


In the calculator: 7.127272727

But if u need it in sig figs: 7.1atm
5 0
3 years ago
A solid is 5 cm tall 3 cm wide and 2 cm thick it has a mass of 129 g what is the density
belka [17]
First you would multiply 5,3, and 2 to get a volume of 30. Density is mass over volume so you would then divide 129 by 30. You would get 4.3. The answer would be 4.3 g/cm^3
7 0
3 years ago
Read 2 more answers
How many amperes would be needed to produce 60.0 grams of magnesium during the electrolysis of molten mgcl 2 in 2.00 hours?
Shalnov [3]

Answer:

\boxed{\text{66.2 A}}

Explanation:

1. Write the equation for the reaction.

M_r:                 24.30

          MgCl₂ ⟶ Mg + Cl₂

m/g:                   60.0

2. Calculate the moles of Mg

Moles of Mg = 60.0 g Mg × (1 mol Mg/ 24.30 g Mg) = 2.469 mol Mg

3. Calculate the moles of electrons

Moles of electrons = 2.469 mol Mg × (2 mol electrons/1 mol Mg)

= 4.938 mol electrons

4. Calculate the number of coulombs

Q = 4.938 mol electrons × (96 485 C/1 mol electrons) = 476 500 C

5. Calculate the current required

Q  = It

I = Q/t

t = 2.00 h × (60 min/1h) × (60 s/1 min) = 7200 s

I = 476 500 C/7600 s= 66.2 C/s = 66.2 A

You need a current of \boxed{\textbf{66.2 A}}.

8 0
4 years ago
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