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alukav5142 [94]
3 years ago
7

Typically, water runs through the baseboard copper tubing and, therefore, fresh hot water is constantly running through the pipi

ng. However, consider a pipe where water was allowed to sit in the pipe. The hot water cools as it sits in the pipe. What is the temprature change, (ΔT), of the water if 210.0 g of water sat in the copper pipe from part A, releasing 3178 J of energy to the pipe? The specific heat of water is 4.184 (J/g)⋅∘C.
Chemistry
1 answer:
Ugo [173]3 years ago
6 0

Answer:

-3.617 °C

Explanation:

Step 1: Given data

Mass of water (m): 210.0 g

Energy released in the form of heat (Q): -3178 J (the minus sign corresponds to energy being released)

Specific heat of water (c): 4.184 J/g.°C

Temperature change (ΔT): ?

Step 2: Calculate the temperature change

We will use the following expression.

Q = c × m × ΔT

-3178 J = 4.184 J/g.°C × 210.0 g × ΔT

ΔT = -3.617 °C

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1. Which is the metric standard for measuring energy?

The <u>metric standard for measuring of energy </u>defined by the International System of Units is the joule (J), which is defined as the work done by a force of a newton in a displacement of one meter in the direction of force. So,

1 J = 1 N m = 1 kg·m²/s²

Calorie is also frequently used in scientific and technological applications. Calorie is a <u>unit of thermal energy that is equivalent to the amount of heat needed to raise the temperature of 1 gram of water by 1 degree Celsius</u>.

1 cal = 4,184 J

2. Which unit is used for specific heat capacity?

The specific heat capacity (c) is a physical quantity that is defined as the <u>amount of heat (</u><u>q</u><u>) that must be supplied to the mass unit of a thermodynamic substance or system to raise its temperature by one unit.</u> So,

c = q / m ΔT

where m is the mass of the substance and ΔT is the temperature increase.

In this way, as heat is a form of energy, the International System of Units expresses the specific heat in <u>joules per kilogram and per kelvin</u> (J kg⁻¹ K⁻¹). Another common unit, not belonging to the SI, is the <u>calorie per gram and per degree centigrade</u> (cal g⁻¹ ° C⁻¹).

3. If you wanted to compare the abilities of olive oil and peanut oil to gain or lose thermal energy, which unit would you use?

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A chemist has to prepare 250.0 mL of a 0.300 M Na2SO4(aq) solution. What mass, in grams, of sodium sulfate (formula mass 142.05
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The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g

<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>
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Mole = Molarity x Volume

Mole of Na₂SO₄ = 0.3 × 0.25

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<h3>How to determine the mass of sodium sulphate Na₂SO₄</h3>
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Learn more about molarity:

brainly.com/question/15370276

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