Combustion reaction because it produces water and carbon dioxide
Answer:
the molecular formula of the compound is N2O4
Explanation:
- Find the empirical formula
mole of N present = mass of N divided by molar mass of N = 0.140/14 = 0.01 mole
mole of O present = mass of O divided by molar mass of O = 0.320/16 = 0.02 mole
Divide both by the smallest number of mole to determine the coefficient of each, the smallest number of mole is 0.01 thus:
quantity of N = 0.01/0.01 = 1
quantity of O = 0.02/0.01= 2
thus the empirical formula = NO2
- Now determine the molecular formula by finding the ratio of molecular formula and empirical formula
Molar mass of molecular formula = 92.02 amu = 92.02 g/mole
Molar mass of empirical formula NO2 = (14 + (16 x 2)) = 46 g/mole
the x factor = 92.02/46 = 2
Molecular formula = 2 x NO2 = N2O4
I'm not completely sure but I think it is 27.4572. Hope I helped a little.
Answer : The correct option is, (A) 51.1%
Explanation :
Mass percent : It is defined as the mass of the given component present in the total mass of the compound.
Formula used :
First we have to calculate the mass of 
and 
.
Mass of = 18 g/mole
Mass of 
= 7 × 18 g/mole = 126 g/mole
Mass of = 246.47 g/mole
Now put all the given values in the above formula, we get the mass percent of in .
Therefore, the mass percent of in is, 51.1%
