Moles of Oxygen= 2.8075 moles
<h3>Further explanation</h3>
Given
29.2 grams of acetylene
Required
moles of Oxygen
Solution
Reaction(Combustion of Acetylene) :
2 C₂H₂ (g) + 5 O₂ (g) ⇒ 4CO₂ (g) + 2H₂O (g)
Mol of Acetylene :
= mass : MW Acetylene
= 29.2 g : 26 g/mol
= 1.123
From equation, mol ratio of Acetylene(C₂H₂) : O₂ = 2 : 5, so mol O₂ :
= 5/2 x mol C₂H₂
= 5/2 x 1.123
= 2.8075 moles
Answer:
H₂O
Explanation:
Chemical equation:
C₅H₁₂ + O₂ → CO₂ + H₂O
Balanced chemical equation:
C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O
The given reaction is combustion reaction. The balance equation shows that there are equal number of moles of carbon, hydrogen and oxygen on both side of equation thus it follows the law of conservation of mass.
Combustion reaction:
The reaction in which substance react with oxygen and produced carbon dioxide and water.
Mostly hydrocarbons burns in the presence of oxygen and form carbon dioxide and water.
Answer:
[PCl₃] = 0.031M
[Cl₂] = 0.031M
[PCl₅] = 0.969M
Explanation:
Based on the reaction:
PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)
Keq is defined as:
<em>Keq = 1.0x10⁻³ = [PCl₃] [Cl₂] / [PCl₅]</em>
<em>Where [] are equilibrium concentrations of each species</em>
Inital [PCl₅] = 2.0mol / 2.0L = 1M.
In equilibrium:
[PCl₃] = X
[Cl₂] = X
[PCl₅] = 1M-X
Where X is reaction coordinate
Solving for X in Keq:
1.0x10⁻³ = [X] [X] / [1-X]
1.0x10⁻³ - 1.0x10⁻³X = X²
1.0x10⁻³ - 1.0x10⁻³X - X² = 0
X:
X = -0.032M. False solution, there is no negative concentration
X = 0.031M
That means equlibrium concentrations are:
[PCl₃] = 0.031M
[Cl₂] = 0.031M
[PCl₅] = 1-0.031M = 0.969M
<h3>[PCl₃] = 0.031M</h3><h3>[Cl₂] = 0.031M</h3><h3>[PCl₅] = 0.969M</h3>
