...clutching am I.Sedimentary
Answer:
(x+10) (x+3)
Explanation:
1) this quadratic equation is in the form of: ax^2+bx+c
where we need to figure out what*what=c(30)
and what+what=13(b)
factors of 30: -1,-30 1,30 2,15 -2,-15 3,10 -3,-10 5,6 -5,-6
factors of 30 which equal 13: 3,10
lets substitute 3 and 10 in lace of 13x to factor by grouping:
x^2+3x+10x+30
make two sets:
set a) x^2+3x
set b) 10x+30
the GCF in set a is "x":
x(x+3)
The Gcf in set b is 10:
10(x+3)
now combine the terms outside the parantheses:
(x+10)(x+3)=0
Hope this helps!
The Mass number is 65, Copper-65
To find the mass number you add the number of protons to the number of neutrons.
