Let's eliminate these one by one.
The first pair would not be the same, as X would most likely be in group IA, and Y would be in group VIIA, because of their tendency to gain and lose electrons.
The second pair would also violate the same rule, but X would most likely be in group IIA, and Y would most likely be in group VIA.
The third pair would not be the same, as X is most likely in group VIIA, and since Y has eight valence electrons, it is most likely a noble gas.
The final pair has X with atomic number 15, making it phosphorous. Phosphorous wants to gain 3 electrons to have a full octet of 8 outer "valence" electrons, and Y would also like to gain 3 electrons. This means it is possible that the final pair would be in the same group.
Answer:
The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is ![5.23\times 10^{-5} m](https://tex.z-dn.net/?f=5.23%5Ctimes%2010%5E%7B-5%7D%20m)
Explanation:
Given :
The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:
![E=\frac{R_y}{n^2}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BR_y%7D%7Bn%5E2%7D)
= Rydberg energy
n = principal quantum number of the orbital
Energy of 11th orbit = ![E_{11}](https://tex.z-dn.net/?f=E_%7B11%7D)
![E_{11}=\frac{2.18\times 10^{-18} J}{11^2}=1.80\times 10^{-20} J](https://tex.z-dn.net/?f=E_%7B11%7D%3D%5Cfrac%7B2.18%5Ctimes%2010%5E%7B-18%7D%20J%7D%7B11%5E2%7D%3D1.80%5Ctimes%2010%5E%7B-20%7D%20J)
Energy of 10th orbit = ![E_{10}](https://tex.z-dn.net/?f=E_%7B10%7D)
![E_{10}=\frac{2.18\times 10^{-18} J}{10^2}=2.18\times 10^{-20} J](https://tex.z-dn.net/?f=E_%7B10%7D%3D%5Cfrac%7B2.18%5Ctimes%2010%5E%7B-18%7D%20J%7D%7B10%5E2%7D%3D2.18%5Ctimes%2010%5E%7B-20%7D%20J)
Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.
![E'=E_{10}-E_{11}=2.18\times 10^{-20} J-1.80\times 10^{-20} J](https://tex.z-dn.net/?f=E%27%3DE_%7B10%7D-E_%7B11%7D%3D2.18%5Ctimes%2010%5E%7B-20%7D%20J-1.80%5Ctimes%2010%5E%7B-20%7D%20J)
![=E'=0.38\times 10^{-20} J](https://tex.z-dn.net/?f=%3DE%27%3D0.38%5Ctimes%2010%5E%7B-20%7D%20J)
(Planck's' equation)
![\lambda = \frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{0.38\times 10^{-20} J}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7B6.626%5Ctimes%2010%5E%7B-34%7D%20Js%5Ctimes%203%5Ctimes%2010%5E8%20m%2Fs%7D%7B0.38%5Ctimes%2010%5E%7B-20%7D%20J%7D)
![\lambda = 5.2310\times 10^{-5} m\approx 5.23\times 10^{-5} m](https://tex.z-dn.net/?f=%5Clambda%20%3D%205.2310%5Ctimes%2010%5E%7B-5%7D%20m%5Capprox%205.23%5Ctimes%2010%5E%7B-5%7D%20m)
The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is ![5.23\times 10^{-5} m](https://tex.z-dn.net/?f=5.23%5Ctimes%2010%5E%7B-5%7D%20m)
Answer:
There are 79 protons in the nucleus of one Gold atom.
Explanation:
The number of protons of any given atom/element can be determined by the atomic number of the specific element, which is found on the periodic table.
Answer:
C
Explanation: a is incorrect since the lower the ph = more acidic and b is incorrect because it produces hydronium ion and d I’m not sure what it is but I no that base recieve the protons
Explanation: Heat capacity is the amount of heat required to change the temperature of a ... Therefore, specific heat is measured in Joules per g times degree Celsius