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Nata [24]
3 years ago
8

Titration of 25.0 mL of an HCl solution of unknown concentration requires 14.8 mL of 0.100 M NaOH. What is the molar concentrati

on of the HCl solution
Chemistry
1 answer:
nordsb [41]3 years ago
4 0
M1V1 = M2V2
M1 = 0.100 M NaOH
V1 = 14.8 mL NaOH
M2 = ?
V2 = 25.0 mL HCl

(0.100 M)(14.8 mL) = M2(25.0 mL)

M2 = 0.0592 M HCl
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A solution of aqueous ammonium sulfate has a mass of 482 grams. Calculate the mass of ammonium sulfate in solution if the mass p
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Answer:

The answer to your question is the mass of solute = 53.5 g

Explanation:

Data

mass of solution = 482 g

mass of solute = ?

mass percent = 11.1 %

Mass percent is a unit of concentration. It measures the mass of the solute divided by the total mass of the solution

Process

1.- Write the formula

        Mass percent = mass of solute / mass of solution x 100

-Solve for mass of solute

          mass of solute = Mass percent x mass of solution / 100

2.- Substitution

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