Titration of 25.0 mL of an HCl solution of unknown concentration requires 14.8 mL of 0.100 M NaOH. What is the molar concentrati
1 answer:
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Explanation:
The given data is as follows.
Concentration of solution = 0.5 M
Volume of solution = 1 L
Molar mass of Glycylglycine = 132.119 g/mol
As molarity is the number of moles present in liter of solvent.
Mathematically, Molarity =
Hence, calculate the number of moles as follows.
No. of moles = Molarity × Volume
=
= 0.5 mol
Therefore, mass of glycylglycine = mol × molar mass
=
= 66.06 g
Thus, we can conclude that 66.06 g glycylglycine is required.