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2 years ago

I am a 3-digit decimal. The sum of my digits is nine. One of my decimal digits is 0. I have a 3 in my tenths place. Who am I?

1 answer:

6 0

.360 or .306
Because 3 is in the tenths place, there is a 0, and 3+6+0= 3+6=9 the sum of all the digits. And it’s a three digit decimal.

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Given a sphere with radius r, the formula 4pi r^2 gives

Shkiper50 [21]

Answer:

Step-by-step explanation:

That's B: the surface area.

The volume of the sphere is V = (4/3)πr³; A = 4πr² happens to be the derivative of V with respect to r.

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3 years ago

1/7 (x-3) = 5/7 ? solve for x.

yuradex [85]

1/7 (x - 3) = 5/7
1/7x - 3/7 = 5/7
1/7x - 3/7 + 3/7 = 5/7 + 3/7
1/7x = 8/7
1/7x(7) = 8/7(7)
X = 56/7
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3 years ago

-1 - ( -2 ) = Can you help me with this question :)

wolverine [178]

Answer:

-1 - ( -2 ) = 1

Step-by-step explanation:

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2 years ago

Read 2 more answers

The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th

Fantom [35]

Answer:

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C$

Step-by-step explanation:

To find:

∫ $6x^5(x^6-2)\,dx$

Solution:

Method of substitution:

Let $x^6-2=t$

Differentiate both sides with respect to $t$

$6x^5\,dx=dt$

[use $(x^n)'=nx^{n-1}$ ]

So,

∫ $6x^5(x^6-2)\,dx$ = ∫ $t\,dt$ = $\frac{t^2}{2}+C_1$ where $C_1$ is a variable.

(Use ∫ $t^n\,dt=\frac{t^{n+1} }{n+1}$ )

Put $t=x^6-2$

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1$

Use $(a-b)^2=a^2+b^2-2ab$

So,

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C$

where $C=2+C_1$

Without using substitution:

∫ $6x^5(x^6-2)\,dx$ = ∫ $6x^{11}-12x^5\,dx$ = $\frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C$

So, same answer is obtained in both the cases.

7 0

2 years ago

How to find the area of a sector with a sector angle of 72 degrees and a radius of 14 cm

skad [1K]

Answer:

Exact area: 39.2π cm²

Approximate area: 123.2 cm²

Step-by-step explanation:

The area of a circle is πr².

A full circle can be thought of as a sector of a circle with 360° of central angle. For a sector of a circle with a central angle of n°, multiply the area of the circle by the fraction n°/360°.

The formula for the area of a sector of circle with central angle n° and radius r is

A = (n°)/(360°) × πr²

Here we have n = 72; r = 14 cm

A = (n°)/(360°) × πr²

A = (72°)/(360°) × π × (14 cm)²

A = 39.2π cm² = 123.2 cm²

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1 year ago