Answer:
Area of triangle is 25.
Step-by-step explanation:
We have been given an isosceles right triangle
Isosceles triangle is the triangle having two sides equal.
Figure is shown in attachment
By Pythagoras theorem
AD is altitude which divides the triangle into two parts
DC=5 implies BC =10 since D equally divides BC
Let AC=a implies AB=a being Isosceles
On substituting the values in the Pythagoras theorem:
WE can find area of right triangle by considering height AB and AD
Area of triangle ABC is:
(1)
And other method of area of triangle is:
(2)
Equating (1) and (2) we get:
Using area of triangle is:
Now, the area of triangle ABC=
Answer:
3x-8=y
Step-by-step explanation:
Answer:
Mean- the average of data, meaning you add up all the numbers, and then divide the sum of the numbers by how many numbers there are. For example:
2, 2, 3, 4, 6, 6, 9.
7 numbers total.
2 + 2 + 3 + 4 + 6 + 6 + 9 = 32
32 ÷ 7 = 4.57
The mean would be 4.57.
Median- the middle point of the numbers. You cross off each of the numbers until you have one last number standing. If you have an even number of numbers, you find the middle of the last two numbers you crossed off. For example:
2, 2, 3, 4, 6, 6, 9
2, 3, 4, 6, 6
3, 4, 6
4
4 would be the median.
Mode- the largest number on the data.
Range- subtract the mode (largest number) from the smallest number to get range. For example:
2, 2, 3, 4, 6, 6, 9
9 - 2 = 7
7 would be the range.
Step-by-step explanation:
Answer:
Step-by-step explanation:
The first expression is
The sum of the constants is 7+3=10
The sum of the coefficients is 3+7=10
The second expression is;
The sum of the constants is 7+1=8
The sum of the coefficients is 4+4=8
The third expression is;
The sum of the constants is 8+2=10
The sum of the coefficients is 4+8=12
The fourth expression is;
The sum of the constants is 8+4=12
The sum of the coefficients is 3+7=10
Hence the correct choice is the expression in which the sum of the constants greater than the sum of the coefficients
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following functions :
sin^4 (x) = f(g(x)) where f(x) = and g(x) =
Sin⁴(x) = sin(x)⁴
g(x) = sin(x),
f(x) = f(g(x)) = f(sin(x)⁴) = x⁴
2.) sin(sin(x)) = f(g(x)) where f(x) = , and g(x) =
g(x) = sin(x) ; sinx = x
g(x) = sin(x)
f(x) = f(g(x)) = sin(x) ; sin(x) = x
f(x) = f(g(x)) = f(sin(x))
f(x) = sin(x)
3. sin x^4 = f(g(x)) where f (x) = , and g(x) = .
Here,
g(x) = x⁴
f(x) = f(g(x)) = sin(g(x)) = sin x
f(x) = sinx
