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Whitepunk [10]
4 years ago
12

What’s the diameter of the circle of the circumference is 30 pi inches

Mathematics
2 answers:
ICE Princess25 [194]4 years ago
6 0
30?
30pi = 2pi r
30pi / 2pi = 15
15 = r
double the radius to get the diameter
15)2 =30
Mashutka [201]4 years ago
4 0

Answer:

Step-by-step explanation:

The circumference formula for a circle is

C=2\pi r or C=\pi d

We'll use the second one since our problem wants us to find diameter.  If we know that the circumference is 30π, then we will sub in 30π for C and solve for d:

30π = πd so

30π/π = d

The π's cancel out, leaving us with a diameter of 30 inches.

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cestrela7 [59]
Difference = 2.62 miles

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7 0
3 years ago
5-2(3z+2)=-4(1-2z) please help lol
Sveta_85 [38]

Answer:

z= 5/14

Step-by-step explanation:

Let's solve your equation step-by-step.

5−2(3z+2)=−4(1−2z)

Step 1: Simplify both sides of the equation.

5−2(3z+2)=−4(1−2z)

5+(−2)(3z)+(−2)(2)=(−4)(1)+(−4)(−2z)(Distribute)

5+−6z+−4=−4+8z

(−6z)+(5+−4)=8z−4(Combine Like Terms)

−6z+1=8z−4

−6z+1=8z−4

Step 2: Subtract 8z from both sides.

−6z+1−8z=8z−4−8z

−14z+1=−4

Step 3: Subtract 1 from both sides.

−14z+1−1=−4−1

−14z=−5

Step 4: Divide both sides by -14.

−14z/ = -5

−14      -14

=5/14

z= 5/14

3 0
3 years ago
If Brian biked at an average speed of 12.2 miles per hour for 1.45 hours, you can find the total distance by multiplying
spin [16.1K]

Answer:

17.69 miles

Step-by-step explanation:

We are given that Brian is riding his bike with a speed of 12.2 miles per hour . We have to evaluate the distance traveled if he rides his bike for 1.45 hours.

We know that the formula for distance is given as

Distance  = speed * time

Distance = 12.2 * 1.45

Distance = 17.69

Hence Brian travels 17.69  miles.

4 0
3 years ago
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2/6 in its simplest form
cluponka [151]
\frac{2}{6} = \frac{1\times 2}{3\times 2} = \huge{\boxed{\frac{1}{3}}}
3 0
3 years ago
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Let Upper A equals left bracket Start 2 By 2 Matrix 1st Row 1st Column negative 2 2nd Column 4 2nd Row 1st Column 1 2nd Column 3
Yuliya22 [10]

Answer: a) AB = \left[\begin{array}{ccc}-14&26\\-11&22\end{array}\right] ; b) \left[\begin{array}{ccc}5&-5\\13&9\end{array}\right] ; c) No, they are different; d) No, they are never the same;

Step-by-step explanation:

a) A = \left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] , B = \left[\begin{array}{ccc}-2&1\\-3&7\end{array}\right]. This multiplication is possible, because matrix A has 2 columns and matrix B has 2 rows. When those value are equal, the multiplication is possible.

AB = \left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] . \left[\begin{array}{ccc}-2&1\\-3&7\end{array}\right] = \left[\begin{array}{ccc}-14&26\\-11&22\end{array}\right]

b) BA = \left[\begin{array}{ccc}-2&1\\-3&7\end{array}\right] . \left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] = \left[\begin{array}{ccc}5&-5\\13&9\end{array}\right]

c) As, we can see, parts a and b are differents.

d) With matrices, multiplication is not commutative, which means AB≠BA

3 0
4 years ago
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