Answer:
The equation of the line is 6y = 7x + 23
Step-by-step explanation:
We begin by calculating the slope of the line;
mathematically, the slope is given by;
m = (y2-y1)/(x2-x1)
That would be;
m= (5-(-2))/(1-(-5))
m = 7/6
So the equation becomes;
y = 7/6x + b
We below need to get the value of the y-intercept b
We get this by making a substitution for any of the two points
Let’s say we make the substitution for (-5,-2) in which case y = -2 and x = -5
Thus, we have
-2 = 7/6(-5) + b
-2 = -35/6 + b
b = -2 + 35/6
b = (-12+ 35)/6 = 23/6
So we have;
y = 7/6x + 23/6
let’s multiply through by 6
6y = 7x + 23
Answer:
Step-by-step explanation:
3. slope of CB = rise/run = 5/12 BF = 5 CF = 12
BF ⊥ DF
DB (seg of two farthest points) = √BF²+DF² = √5²+32² = √1049 = 32.4
4. f(x) = 2x² - 5x -3 vertex : A (h,k) for f(x) = ax² + bx +c
h = - b/2a = - (-5 / 4) = 5/4
f = f(h) = 2*(5/4)² - 5*(5/4) - 3 =25/8 - 25/4 -3 = -49/8
A (5/4 , - 49/8) i.e. (1.25 , - 6.13)
negative root: 2x² - 5x -3 = (2x+1) (x- 3) x = - 1/2 y = 0
B (- 1/2 , 0)
x coordinate of AB: 1/2 (1.25 + -0.5) = 0.375
17x +x to the second power
Answer:
It cannot be answered if we don't figure out what x means. IF we knew what X is we can multiply 6 by x and then add 7.
an example would be if x was 3. we could figure out the answer by just doing (6*3)+7=25
