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sergejj [24]
2 years ago
14

Solve x+4 ≤ 19 type answer in comments below and post them please.

Mathematics
1 answer:
RoseWind [281]2 years ago
4 0

Answer:

x \leqslant 15

Step-by-step explanation:

To find the answer we have to first group the like terms:

x + 4 \leqslant 19 \:

therefore

x \leqslant 19 - 4

so

x \leqslant 15

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Step-by-step explanation: hope this helps

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Whats the graph after you transition it 6 units left?
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Find a third-degree polynomial function with real coefficients and with zeros at -4 and -3 5i
Charra [1.4K]

If -3+5i is a solution, then by the conjugate root theorem, -3-5i is also a solution. We find the polynomial by multiplying together the factors. If x = -4, then x + 4 is the factor. If x = -3+5i, then (x-(-3+5i)) is a factor, and so is (x-(-3-5i)). Simplifying those down gives us as the first factor as (x+3-5i) and the second as (x+3+5i). We can FOIL those 2 together to get their product, and then FOIL in x+4. FOILing the 2 complex factors together gives us x^2+3x+15ix+3x+9+15i-15ix-15i-25i^2. If we combine like terms and cross out things that cancel it's much easier than what it looks like there! It simplifies down to x^2+6x-25i^2. Since i^2 = -1, it simplifies further to x^2+6x-25(-1) and finally, to x^2+6x+25. Now we will FOIL in x+4. (x^2+6x+25)(x+4)=x^3+6x^2+25x+4x^2+24x+100. Our final simplified third degree polynomial is x^3+10x^2+49x+100

3 0
3 years ago
Write a recursive rule for the sequence.
Vadim26 [7]

Answer:

f(n)=f(n-1)+f(n-2)

f(1)=1x

f(2)=1x

Step-by-step explanation:

This is the fibonacci sequence with each term times x.

Notice, you are adding the previous two terms to get the third term per consecutive triples of the sequence.

That is:

1x+1x=2x

1x+2x=3x

2x+3x=5x

3x+5x=8x

So since we need the two terms before the third per each consecutive triple in the sequence, our recursive definition must include two terms of the sequence. People normally go with the first two.

f(1)=1x since first term of f is 1x

f(2)=1x since second term of f is 1x

Yes, I'm naming the sequence f.

So I said a third term in a consecutive triple of the sequence is equal to the sum of it's two prior terms. Example, f(3)=f(2)+f(1) and f(4)=f(3)+f(2) and so on...

Note, the term before the nth term is the (n-1)th term and the term before the (n-1)th term is the (n-2)th term. Just like before the 15th term you have the (15-1)th term and before that one you have the (15-2)th term. That example simplified means before the 15th term you have the 14th and then the 13th.

So in general f(n)=f(n-1)+f(n-2).

So the full recursive definition is:

f(n)=f(n-1)+f(n-2)

f(1)=1x

f(2)=1x

8 0
3 years ago
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