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umka2103 [35]
3 years ago
7

The elements that contain electrons in an F sublevel near the highest occupied energy level are referred to as?

Chemistry
2 answers:
ser-zykov [4K]3 years ago
8 0

inner transition metals is your answer

Mrac [35]3 years ago
3 0

inner transmission levels i took the test

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the half life of I -137 is 8.07 days. if 24 grams are left after 40.35 days, how many grams were in the original sample?
Ray Of Light [21]

Answer:

768g

Explanation:

We can use to formula N(A) = N_0(\frac{1}{2})^\frac{t}{t_{1/2}} . Here, N(A) is the final amount. N0 is the initial amount. t is the time elapsed, and t_{1/2} is the half life. Plugging in, we get the answer above.

4 0
3 years ago
Why cant you see individual atoms without a special tool​
lesya692 [45]

Answer:

its because atoms are incredibly small its looking for atoms is like placing a blueberry in a foot ball field and looking at it from 10 miles up you cant see that blueberry

Explanation:

6 0
2 years ago
Read 2 more answers
Imagine mixing 1 tablespoon of Epsom salt with 2 cups of ammonia. How much precipitate would be produced? Describe the amount of
barxatty [35]

The amount of precipitate produced will be proportional to the amount of NH₃ reacted with water to produce NH₄OH.

<h3>What is precipitate?</h3>

Precipitates are the crystal type formation, when the solute is no more dissolving in the solvent.

Imagine mixing 1 tablespoon of Epsom salt with 2 cups of ammonia, the reaction is

2NH₃ + MgSO₄ + 2H₂O → Mg(OH)₂ + (NH₄)₂SO₄

The amount of precipitate produced will be proportional to the amount of NH₃ reacted with water to produce NH₄OH.

Learn more about precipitate.

brainly.com/question/18109776

#SPJ1

4 0
1 year ago
2. A block of aluminum with a mass of 140g is cooled from 98.4oC to 62.2oC with a release of 1137J of heat. From these data, cal
NeTakaya
Q =  M * C *ΔT

Q / <span>ΔT  = M

</span>Δf - Δi =  98.4ºC - 62.2ºC = 36.2ºC
<span>
C = 1137 J / 140 * 36.2

C = 1137 / 5068

C = 0.224 J/gºC</span>
8 0
3 years ago
Consider the reaction 2 al + Fe2O3 to 2Fe + Al2O3. If 60.0g of Al is reacted with excess Fe2O3, determine the amount (in moles)
olganol [36]

 The  amount  of  Al2O3  in moles=  1.11 moles    while in  grams   = 113.22 grams


    <em><u>calculation</u></em>

     2 Al  + Fe2O3 → 2Fe  + Al2O3

    step  1: find the moles of Al  by  use of <u><em>moles= mass/molar  mass  </em></u>formula

    =  60.0/27= 2.22  moles


    Step 2: use the mole ratio to determine the  moles of Al2O3.

 The  mole ratio  of Al : Al2O3 is  2: 1 therefore the moles of Al2O3= 2.22/2=1.11  moles


Step 3:    finds the mass  of  Al2O3  by us of  <u><em>mass= moles x molar mass</em></u><em> </em>formula.

The molar  mass of Al2O3  =  (2x27)  +( 16 x3) = 102  g/mol

mass is therefore=  102  g/mol  x 1.11= 113.22 grams


             

7 0
3 years ago
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