Answer:
number of protons: 94
number of neutrons: 145
239
Pu
94
Explanation:
1) The atomic number, Z, of plutonium is Z = 94, i.e plutonium 94 protons
2) Plutoniun-239 is the isotope with mass number 239.
3) Mass number = number of protons + number of neutrons =>
number of neutrons = mass number - number of protons = 239 - 94 = 145
4) The notation requires that you indicate the symbol of the element with the atomic number (number of protons) and the mass number.
You put the mass number as a superscript at the left side of the symbol and the atomic number as subscript to the left of the symbol.
So, in this case the symbol is Pu, the superscript to the left is 239 and the subscript to the left is 94.
239
Pu
94
Answer:
to make sure that the source is reliable.
Explanation:
because I am smart
Which of the following is described by the equation H2O(l) + heat → H2O(g)?
Answer: +H30
Answer: The vapor pressure of water at 298 K is 3.565kPa.
Explanation:
The vapor pressure is determined by Clausius Clapeyron equation:
where,
= initial pressure at 298 K = ?
= final pressure at 373 K = 101.3 kPa
= enthalpy of vaporisation = 41.1 kJ/mol = 41100 J/mol
R = gas constant = 8.314 J/mole.K
= initial temperature = 298 K
= final temperature = 373 K
Now put all the given values in this formula, we get
![\log (\frac{101.3}{P_1})=\frac{41100}{2.303\times 8.314J/mole.K}[\frac{1}{298K}-\frac{1}{373K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7B101.3%7D%7BP_1%7D%29%3D%5Cfrac%7B41100%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B298K%7D-%5Cfrac%7B1%7D%7B373K%7D%5D)
Therefore, the vapor pressure of water at 298 K is 3.565kPa.
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