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Rufina [12.5K]
3 years ago
13

Divide. Write the quotient in lowest terms. 4\dfrac{2}{3} \div 7 =4 3 2 ​ ÷7=4, start fraction, 2, divided by, 3, end fraction,

divided by, 7, equals
Mathematics
1 answer:
velikii [3]3 years ago
3 0

Answer:

\dfrac{2}{3}

Step-by-step explanation:

Given the quotient: 4\dfrac{2}{3} \div 7

Step 1: Write 4\dfrac{2}{3} in improper fraction.

4\dfrac{2}{3}=\dfrac{14}{3}

Therefore:

4\dfrac{2}{3} \div 7=\dfrac{14}{3} \div 7

<u>Step 2:</u> Change the division sign to multiplication by taking the reciprocal of 7

\dfrac{14}{3} \div 7 =\dfrac{14}{3} X\dfrac{1}{7} \\$Simplify\\\\=\dfrac{2}{3}

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Consider 4 flips of an unfair coin where probability of heads is 0.40. Consider all tosses independent of each other. (a) Compar
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Answer:

a) 0.0256 = 2.56% probability of 4 heads.

0.1296 = 12.96% probability of 4 tails.

b) The probability is 0.0576 = 5.76%.

c) 6 outcomes given 2 heads in 4 tosses. 0.3456 = 34.56% probability of 2 heads in 4 tosses

Step-by-step explanation:

For each throw, we have these following probabilities:

0.4 = 40% probability of heads.

0.6 = 60% probability of tails.

(a) Compare the probability of 4 heads in 4 tosses and 4 tails in 4 tosses.

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4 tails:

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p = 0.4*0.6*0.4*0.6 = 0.0576

The probability is 0.0576 = 5.76%.

(c) Determine the number of outcomes that give us 2 heads in 4 tosses in any order. What is the probability of 2 heads in 4 tosses (use (b) and the number of outcomes)

Number of outcomes:

The possible outcomes are:

H - H - T - T

H - T - H - T

H - T - T - H

T - H - H - T

T - H - T - H

T - T - H - H

6 outcomes given 2 heads in 4 tosses.

Each with probability 0.0576, as found in b)

6*0.0576 = 0.3456

0.3456 = 34.56% probability of 2 heads in 4 tosses

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