Help! please i cant figure it out.
1 answer:
let's recall that the graph of a function passes the "vertical line test", however, that's not guarantee that its inverse will also be a function.
A function that has an inverse expression that is also a function, must be a one-to-one function, and thus it must not only pass the vertical line test, but also the horizontal line test.
Check the picture below, the left-side shows the function looping through up and down, it passes the vertical line test, in green, but it doesn't pass the horizontal line test.
now, check the picture on the right-side, if we just restrict its domain to be squeezed to only between [0 , π], it passes the horizontal line test, and thus with that constraint in place, it's a one-to-one function and thus its inverse is also a function, with that constraint in place, or namely with that constraint, cos(x) and cos⁻¹(x) are both functions.
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Answer:
3x + 5y = 1
Step-by-step explanation:
the equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
Obtain the equation in slope- intercept form
y = mx + c ( m is the slope and c the y-intercept )
to calculate m use the gradient formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = (- 3, 2) and (x₂, y₂ ) = (2, - 1) ← 2 points on the line
m = = -
y = - x + c ← is the partial equation
to find c substitute either of the 2 points into the partial equation
using (2, - 1), then
- 1 = - + c ⇒ c = - 1 +
=
y = - x +
← in slope-intercept form
multiply all terms by 5
5y = - 3x + 1 ( add 3x to both sides )
3x + 5y = 1 ← in standard form