This is an incomplete question, here is a complete question.
Draw a Lewis structure for H₂O that obeys the octet rule if possible and answer the following questions based on your drawing.
For the central oxygen atom:
The number of lone pairs =
The number of single bonds =
The number of double bonds =
Answer : The Lewis structure for H₂O is shown below.
For the central oxygen atom:
The number of lone pairs = 4
The number of single bonds = 2
The number of double bonds = 0
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
The representation of valence electrons of an atom by dots around the symbol of an element is said to be the Lewis-dot symbol.
In the representation of Lewis-symbol, one electron dot must put on each side of the element symbol then paired the electrons.
The given molecule is,
As we know that hydrogen has '1' valence electrons and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in = 2(1) + 6 = 8
According to Lewis-dot structure, there are 4 number of bonding electrons and 4 number of non-bonding electrons.
For the central oxygen atom:
The number of lone pairs = 4
The number of single bonds = 2
The number of double bonds = 0
Answer:
C₁₂H₂₂O₁₁ and CH₃OH
Explanation:
Sucrose and methyl alcohol are nonelectrolytes. They do not ionize or conduct a current in aqueous solution.
HC₂H₃O₂ is a weak electrolyte. It produces only a few ions and is a poor conductor of electricity in aqueous solution.
HC₂H₃O₂ + H₂O ⇌ H₃O⁺ + C₂H₃O₂⁻
H₂SO₄ is a strong electrolyte. Its first ionization is complete, so it is a good conductor of electricity in aqueous solution.
H₂SO₄ + H₂O ⟶ H₃O⁺ + HSO₄⁻
Answer:
12.5 g
Explanation:
<em>12.5 g of the compound would be formed.</em>
First, let us look at the balanced equation of reaction.
3 moles of Mg is required to react with 1 mole of N2 to produce 1 mole of product.
<em>Recall that: mole = mass/molar mass</em>
9.03 g of Mg = 9.03/24.3 = 0.3716 mole
3.48 g of N2 = 3.48/28 = 0.1243 mole
Mole ratio of Mg/N2 = 3:1
<em>Hence, there is no limiting reactant.</em>
3 moles of Mg is required for 1 mole of product.
0.3716 mole of Mg will therefore require:
0.3716 x 1/3 = 0.1239 moles of product.
Molar mass of product = 100.9 g/mol
Mass of 0.1239 mole = mole x molar mass
= 0.1239 x 100.9 = 12.5 g