Draw a Lewis structure for H2O that obeys the octet rule if possible and answer the following questions based on your drawing. 1
. For the central oxygen atom:
1 answer:
This is an incomplete question, here is a complete question.
Draw a Lewis structure for H₂O that obeys the octet rule if possible and answer the following questions based on your drawing.
For the central oxygen atom:
The number of lone pairs =
The number of single bonds =
The number of double bonds =
Answer : The Lewis structure for H₂O is shown below.
For the central oxygen atom:
The number of lone pairs = 4
The number of single bonds = 2
The number of double bonds = 0
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
The representation of valence electrons of an atom by dots around the symbol of an element is said to be the Lewis-dot symbol.
In the representation of Lewis-symbol, one electron dot must put on each side of the element symbol then paired the electrons.
The given molecule is,
As we know that hydrogen has '1' valence electrons and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in = 2(1) + 6 = 8
According to Lewis-dot structure, there are 4 number of bonding electrons and 4 number of non-bonding electrons.
For the central oxygen atom:
The number of lone pairs = 4
The number of single bonds = 2
The number of double bonds = 0
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The question is incomplete, complete question is :
In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas to produce gaseous ammonia. This reaction is now the first step taken to make most of the world's fertilizer. Suppose a chemical engineer studying a new catalyst for the Haber reaction finds that 348 liters per second of dinitrogen are consumed when the reaction is run at 205°C and 0.72 atm. Calculate the rate at which ammonia is being produced.
Answer:
The rate of production of ammonia is 217.08 grams per second.
Explanation:
Volume of dinitrogen used in a second = 348 L
Temperature of the gas = T = 205°C = 205+273 K = 478 K
Pressure of the gas = P = 0.72 atm
Moles of dinitrogen = n
According to reaction, 1 mole of dinitriogen gives 2 mole of ammonia.Then 6.385 moles of dinitrogen will give:
Mass of 12.769 moles of ammonia;
12.769 mol 17 g/mol = 217.08 g
217.08 grams of ammonia is produced per second.So, the rate of production of ammonia is 217.08 grams per second.