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Nataly [62]
3 years ago
15

A solution has [H+] = 2.35 × 10-3 M. Find the [OH-] for this solution

Chemistry
1 answer:
Aleks04 [339]3 years ago
3 0

Answer:

[OH-] for this solution is 4.255*10^-12

Explanation:

We are given

[H+] = 2.35 × 10-3 M

we need to find the concentration of [OH-]

we know from Equilibrium

[H+][OH-] = 10^-14

[OH-] = 10^14/2.35*10^10^-3

[OH-] = 0.4255*10^-11

[OH] = 4.255*10^-12

Therefore the Concentration  of [OH-] for this solution is 4.255*10^-12

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What is the covalent bond for Hydrogen + Chlorine (HCI)
kolbaska11 [484]

Answer:

HCl, also known as hydrochloric acid, has a covalent bond. The hydrogen (H) atom shares an electron with the chlorine (Cl) to form the bond.

Explanation:

Consequently, the bonding electrons in hydrogen chloride are shared unequally in a polar covalent bond. The molecule is represented by the conventional Lewis structure, even though the shared electron pair is associated to a larger extent with chlorine than with hydrogen.

6 0
3 years ago
Design an invitation you could use to calculate the density of a penny
Nataliya [291]
Firstly, the density of any substance is represented by the mass (amount of matter) as divided by the volume(amount of space). According to external websites, the mass of a penny is 2.5 grams.However, the volume of a penny is .35cm to the power of 3 (due to the thickness of the penny being extremely minimal.Thus the amount of density is extremely little). Therefore, the density of a penny is 0.875 g/cm cubed (dimensional analysis).As for an invention that could be used, that is possible with the usage of a series of measurements that can both calculate mass and volume and directly allocate that to attain density
7 0
4 years ago
Really need help with this<br> Will give brainliest to whoever has the correct answer
lukranit [14]

Answer:

a=0.4\ m/s^2

Explanation:

1. Given that,

Initial speed of a bicycle, u = 4 m/s

The final speed of a bicycle, v = 6 m/s

Time, t = 6 s

We need to find the acceleration of the bicycle. We know that, acceleration is    equal to the change in speed divided by time taken. So,

a=\dfrac{v-u}{t}\\\\a=\dfrac{6-4}{5}\\\\a=0.4\ m/s^2

So, the acceleration of the bicycle is equal to 0.4\ m/s^2.

5 0
3 years ago
Identify the compound that has the same structure as sodium chloride. identify the compound that has the same structure as sodiu
olga_2 [115]
Sodium chloride is an ionic compound. ionic compound is when the compound itself is made up of a metal and non-metal element.
thus the answer is potassium bromide and cesium chloride.
8 0
3 years ago
Read 2 more answers
(b) The conductivity of a 0.01 mol dm–3 solution of a monobasic organic acid in water is 5.07 × 10–2 S m–1. If the molar conduct
Zarrin [17]

Explanation:

The given data is as follows.

   \Lambda^{o}_{m}(NaCl) = 1.264 \times 10^{-2}

   \Lambda^{o}_{m}(H-O=C-ONO) = 1.046 \times 10^{-2}

   \Lambda^{o}_{m}(HCl) = 4.261 \times 10^{-2}

Conductivity of monobasic acid is 5.07 \times 10^{-2} S m^{-1}

     Concentration = 0.01 mol/dm^{3}

Therefore, molar conductivity (\Lambda_{m}) of monobasic acid is calculated as follows.

                 \Lambda_{m} = \frac{conductivity}{concentration}

                                  = \frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol/dm^{3}}

                                 = \frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol \times 10^{3}}

                                 = 5.07 \times 10^{-3} S m^{2} mol^{-1}

Also, \Lambda^{o}_{m} = \Lambda^{o}_{m}_{(HCl)} + \Lambda^{o}_{m}_{(H-O=C-ONO)} - \Lambda^{o}_{m}_{(NaCl)}

                            = 4.261 \times 10^{-2} + 1.046 \times 10^{-2} - 1.264 \times 10^{-2}

                            = 4.043 \times 10^{-2} S m^{2} mol^{-1}

Relation between degree of dissociation and molar conductivity is as follows.

               \alpha = \frac{\Lambda_{m}}{\Lambda^{o}_{m}}

                             = \frac{5.07 \times 10^{-2} S m^{-1}}{4.043 \times 10^{-2} S m^{2} mol^{-1}}

                             = 0.1254

Whereas relation between acid dissociation constant and degree of dissociation is as follows.

                     K = \frac{c \times \alpha^{2}}{1 - \alpha}

Putting the values into the above formula we get the following.

                     K = \frac{c \times \alpha^{2}}{1 - \alpha}

                        = \frac{0.01 \times (0.1254)^{2}}{1 - 0.1254}

                        = 0.017973 \times 10^{-2}

                       = 1.7973 \times 10^{-4}

Hence, the acid dissociation constant is 1.7973 \times 10^{-4}.

Also, relation between pK_{a} and K_{a} is as follows.

                 pK_{a} = -log K_{a}

                              = -log (1.7973 \times 10^{-4})

                              = 3.7454

Therefore, value of pK_{a} is 3.7454.

                             

3 0
3 years ago
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