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Amiraneli [1.4K]
3 years ago
7

Какая система называется моделью химия

Chemistry
2 answers:
OlgaM077 [116]3 years ago
8 0
I don’t understand, what does that say in english?
lutik1710 [3]3 years ago
3 0

Answer:

Я уверен, что это модель Бора

Я могу ошибаться

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24. a. Suppose different parts of a sample material
yaroslaw [1]

Answer:

One can conclude that the metal is an alloy.

Explanation:

An alloy is a combination of metal that has two or more elements. Different metals are usually combined to give it more strength or make it more resistant to corrosion.

Cheers!

7 0
3 years ago
If your car gets 30.3 mi/gal, how many gallons of gasoline would you use if you drove 506.3 miles? 1 mile = 5280 ft (exactly) In
Salsk061 [2.6K]

Answer: 16.7 gallon

Explanation:

Given: The car can drive 30.3 miles when 1 gallon of gasoline is used.

Distance covered = 506.3 miles

Thus for 30.3 miles, the amount of gasoline used= 1 gallon

For 506.3 miles, the amount of gasoline used=\frac{1}{30.3}\times 506.3=16.7gallon

Thus the amount of gasoline used is 16.7 gallons.


4 0
3 years ago
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Idk this question and I need help
Nadusha1986 [10]

Answer:

12 ML

Explanation:

BECAUSE THE WATER ROSE 12 ML SO THE KEY IS 12 ML

8 0
3 years ago
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During an experiment, 104 grams of calcium carbonate reacted with an excess amount of hydrochloric acid. If the percent yield of
postnew [5]

Answer:

92.4 grams.

Explanation:

  • From the balanced reaction:

<em>CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O,</em>

1.0 mole of CaCO₃ reacts with 2.0 moles of HCl to produce 1.0 mole of CaCl₂, 1.0 mole of CO₂, and 1.0 mole of H₂O.

  • We need to calculate the no. of moles of (104 g) of CaCO₃:

<em>no. of moles of CaCO₃ = mass/molar mass</em> = (104 g)/(100.08 g/mol) = <em>1.039 mol.</em>

<u><em>Using cross multiplication:</em></u>

1.0 mole of CaCO₃ produce → 1.0 mole of CaCl₂.

∴ 1.039 mole of CaCO₃ produce → 1.039 mole of CaCl₂.

∴ The amount of CaCl₂ produced = no. of moles x molar mass = (1.039 mol)(110.98 g/mol) = 114.3 g.

∵ percent yield of the reaction = [(actual yield)/(theoretical yield)] x 100.

Percent yield of the reaction = 80.15%, theoretical yield = 115.3 g.

<em>∴ actual yield = [(percent yield of the reaction)(theoretical yield)]/100 </em>= [(80.15%)/(115.3 g)] / 100 = <em>92.42 g ≅ 92.4 g.</em>

7 0
3 years ago
how many moles of NaCl are dissolved in 250 mL of solution if the solution concentration is 0.150 M?​
aliya0001 [1]
What lol I am just answering so I can get points :)
5 0
3 years ago
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