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gladu [14]
3 years ago
10

8hiobhjgjgjvygvm,dfndfjkgnvabjchdbsnfbhj

Mathematics
2 answers:
Oxana [17]3 years ago
7 0

Answer:

Sngkadhmvg,jkr.ufdyhfvfakrthlDKFg/horig

sacagawea is my mommy

Step-by-step explanation:

Pavlova-9 [17]3 years ago
4 0

Answer:

d

Step-by-step explanation:

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Data: (12 ,8 , 6 , 12 , 16 , 12 ) median ............. mode......
Vesna [10]
Ascending order=  6, 8, 12, 12, 12, 16

No of observations (n) = 6
Median = Mean of the values of (n/2) and (n/2+1)
             = Mean values of 3rd and 4th values
             = 12+12/2
             = 12
Therefore, median = 12

Mode = Most number of observations= 12
4 0
3 years ago
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Please help me on this problem!!!
skelet666 [1.2K]

Answer:

2.79166666667

Step-by-step explanation:

7 0
3 years ago
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A science fair poster is a rectangle 36 inches long and 24 inches wide what is the area of the poster in square feet
ella [17]
Well it has to be 3*2 = 6 square feet.  Note: first convert 36 inches to 3 feet and 24 inches to 2 feet.
6 0
3 years ago
According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e
slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that p = 0.09

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

So

P(X < 4) + P(X \geq 4) = 1

We want P(X \geq 4)

So

P(X \geq 4) = 1 - P(X < 4)

In which

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.09)^{0}.(0.91)^{12} = 0.3225

P(X = 1) = C_{12,1}.(0.09)^{1}.(0.91)^{11} = 0.3827

P(X = 2) = C_{12,2}.(0.09)^{2}.(0.91)^{10} = 0.2082

P(X = 3) = C_{12,3}.(0.09)^{3}.(0.91)^{9} = 0.0686

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3225 + 0.3827 + 0.2082 + 0.0686 = 0.982

Finally

P(X \geq 4) = 1 - P(X < 4) = 1 - 0.982 = 0.0180

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

6 0
3 years ago
Will give brainliest give the answer and steps
tester [92]

Answer:B=8

Step-by-step explanation:

3 0
3 years ago
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