Can you guyz help me with this question step by step please ☺️

Mathematics

1 answer:

zlopas [31]2 years ago

7 0

2 1/2 x 3 = 7 1/2 = 7 4/8

10 11/8
- 7 4/8
3 7/8
A is the correct answer

You might be interested in

How am i supposed to solve this ?

Rama09 [41]

Answer:

Step-by-step explanation: so first you got to distribute the on both sides so like the 2 and the ten from there you just eliminate and do it like normal. I’m sorry I’m bad at at explaining it but I hoped it helped some how :)

4 0

2 years ago

Helppp meee pleaseeee!!!!

never [62]

Answer:

each triangle should weigh 2.5!

Step-by-step explanation:

each sides are equal. the side with only squares weighs 25. the squares on the opposite side weigh 10. 25-10 is equal to 15. there are 6 triangles. 15 divided by six gets you 2.5

8 0

2 years ago

Read 2 more answers

vRichard has a red card (R) and a black card (B). He picks a card randomly from the pair and then rolls a six-sided die. The sam

Alik [6]

The Sample space for three cards is

$S=\left\{\left(B,1\right),\left(R,1\right),\left(G,1\right),\left(B,2\right),\left(R,2\right),\left(G,2\right),\left(B,3\right),\left(R,3\right),\left(G,3\right),\left(B,4\right),\left(R,4\right),\left(G,4\right)$ $\left(B,5\right),\left(R,5\right),\left(G,5\right),\left(B,6\right),\left(R,6\right),\left(G,6\right) \right \}$

There are two cards red(R) and black(B) and a six-sided die.

The event is one card is picked randomly and then rolls the die.

So, the Sample space is as follows.

$S=\left\{\left(B,1\right),\left(R,1\right),\left(B,2\right),\left(R,2\right),\left(B,3\right),\left(R,3\right),\left(B,4\right),\left(R,4\right),\left(B,5\right),\left(R,5\right),\left(B,6\right),\left(R,6\right) \right \}$

<h3>Find Sample space if there are three cards.</h3>

Consider there were three cards red(R), black(B) and green(G) a six-sided die.

The event is one card is picked randomly and then rolls the die.

So, the sample space will be as follows,

$S=\left\{\left(B,1\right),\left(R,1\right),\left(G,1\right),\left(B,2\right),\left(R,2\right),\left(G,2\right),\left(B,3\right),\left(R,3\right),\left(G,3\right),\left(B,4\right),\left(R,4\right),\left(G,4\right)$ $\left(B,5\right),\left(R,5\right),\left(G,5\right)\left(B,6\right),\left(R,6\right),\left(G,6\right) \right \}$ .