Ask question

Ask question

All categories

3 years ago

5

Find the mean absolute deviation for the set of data. Number of sibblings 2,5,8,9,7/6,3,5,1,4,

1 answer:

Tresset [83]3 years ago

7 0

8,7,9,3,4,9,2

This is correct because I’m in middle school

You might be interested in

Tracy McKinney is a disc jockey at radio station WMMM. Her annual salary is $52,750. What is her monthly salary?

attashe74 [19]

Okay, so since her annual salary is <span>$52,750 (the amount she gets a year, all twelve months combined) you're trying to find how much she gets monthly. That would mean we would have to divide her annual salary by 12 to find her monthly salary.

</span>$52,750 ÷ 12 = 4,395.8333333333333
<span>
And since that's a (bothersome) repeating decimal, we're going to have to round it. Once rounded, you would get $</span>4,395.83. That is her monthly salary.

5 0

3 years ago

Shawna bought a bag of candy. She ate of the bag on Friday and of the bag on Saturday. What portion of the bag is left?

vodka [1.7K]

Answer:

I believe it would be A hope this helps!

Step-by-step explanation:

5 0

3 years ago

Law of radicals

andrey2020 [161]

Answer:

1) $\sqrt{x^7}=x^{\frac{7}{2}$

2) $\sqrt[3]{y^5}=y^{\frac{5}{3}$

3) $\sqrt[5]{a^{12}}=a^{\frac{12}{5} }$

4) $\sqrt[4]{z^{9}}=z^\frac{9}{4}$

Step-by-step explanation:

1) $\sqrt{x^7}$

We know that $\sqrt{x}=x^{\frac{1}{2}$

So, $\sqrt{x^7}=x^{\frac{7}{2}$

2) $\sqrt[3]{y^5}$

We know that $\sqrt[3]{x}=x^{\frac{1}{3}$

So, $\sqrt[3]{y^5}=y^{\frac{5}{3}$

3) $\sqrt[5]{a^{12}}$

We know that $\sqrt[5]{x}=x^{\frac{1}{5}$

So, $\sqrt[5]{a^{12}}=a^{\frac{12}{5} }$

4) $\sqrt[4]{z^{9}}$

We know that $\sqrt[4]{x}=x^{\frac{1}{4}$

So, $\sqrt[4]{z^{9}}=z^\frac{9}{4}$

6 0

3 years ago

While studying abroad, Linda wants to make 4 batches of her mother's enchilada recipe to feed her classmates. The recipe calls f

tankabanditka [31]

Answer:

ambut lnghsks jsbdjjdidbeh hi dnsvvs

4 0

3 years ago

If x varies directly as y, find x when y=8. x=11 when y=-3

andriy [413]

Answer:

$x=-\frac{88}{3}$

Step-by-step explanation:

When a quantity "A" varies DIRECTLY with another quantity "B", we can write the proportionality equation as:

A = kB

Where k is the proportionality constant (to be found)

In this problem, it is given x varies DIRECTLY with y, so we can write:

x = ky

Also, given, x = 11, y = -3, so we plug these into the equation and first find k:

x = ky

11 = k(-3)

k = -11/3

Now, we need to find x when y = 8, so we substitute and find x:

$x=ky\\x=(-\frac{11}{3})(8)\\x=-\frac{88}{3}$

8 0

3 years ago