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3 years ago

How do I solve 5 + 6y = 9y + 2 + 3(1 - y)

2 answers:

5 0

First, simplify this equation as much as you can.

<span>5 + 6y = 9y + 2 + 3(1 - y)
Use the distributive property on the </span>3(1 - y) part.
3 • 1 = 3
3 • -y = -3y

5 + 6y = 9y + 2 + 3 + -3y
Combine like terms.
The like terms are:
9y and -3y
2 and 3
9y - 3y = 6y
2 + 3 = 5

5 + 6y = 6y + 5
This can not be simplified further, since doing so would only result in 0.
So no matter what y is, this is true.
If you were to fully simplify this, it would be 0 = 0.

Hope this helps!

Stella [2.4K]3 years ago

3 0

Actually you can't solve this. There is no solutions.

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x = 41
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Step-by-step explanation:

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2 years ago

In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the

emmasim [6.3K]

Answer:

$a=\frac{2S -2v_ot-2s_o}{t^2}$

Step-by-step explanation:

We have the equation of the position of the object

$S = \frac{1}{2}at ^2 + v_ot+s_o$

We need to solve the equation for the variable a

$S = \frac{1}{2}at ^2 + v_ot+s_o$

Subtract $s_0$ and $v_0t$ on both sides of the equality

$S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o$

$S -v_ot-s_o = \frac{1}{2}at ^2$

multiply by 2 on both sides of equality

$2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2$

$2S -2v_ot-2s_o =at ^2$

Divide between $t ^ 2$ on both sides of the equation

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3 years ago

Write an equation in slope-intercept form that represents the graphed function.

damaskus [11]

Answer: Y = 1/4x - 2
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M is slope, and b is y intercept

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change in y over change in x is slope
The change in y from (0,-2) and (4,-1) is up one over four.
This can be represented as 1/4

Solving y-intercept:
Y-intercept is when x = 0 or when the line touches the y axis
As you can see on the graph, the y intercept is (0,-2) or -2

Final:
Y = 1/4x - 2

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2 years ago