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Karolina [17]
3 years ago
8

Will give brainliest for answer

Mathematics
1 answer:
sleet_krkn [62]3 years ago
7 0

Answer:

  y > -x -3

Step-by-step explanation:

The graph is shaded <em>above</em> the <em>dashed</em> line, indicating y-values in the solution are greater than those on the line, so your inequality will start with ...

  y >

The y-intercept of the line is (0, -3), so the "b" value in ...

  y > mx +b

will be -3.

The line has a rise of -3 for a run of 3 (between the marked points), so the slope is ...

  m = rise/run = -3/3 = -1

Then the inequality you want is ...

  y > -x -3

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30000 is the answer as it is ajove 20000 in comparison to rounding down
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What type of angles are&lt; 1 and &lt;5?
belka [17]

Answer:

The type of angles of <1 and <5 are corresponding angles

Step-by-step explanation:

3 0
3 years ago
Write a rule for the linear function whose graph has slope m and contains the given point.
Kitty [74]
The rule for the linear graph is y=mx
6 0
3 years ago
2. Match the shapes given to their correct areas.
aliina [53]

Applying the formula for each identified shape that are given, the correct areas to each shape are:

a. <em>Square </em>= 134.6 sq. yd

b. <em>Circle </em>= 452.2 sq. cm

c. <em>Parallelogram </em>= 40.6 sq. cm

d. <em>Rectangle </em>= 43.2 sq. ft

e. <em>Trapezium </em>= 25.7 sq. m

f. <em>Triangle</em> = 21.6 sq. ft

a. The shape given is a square.

Area of the square = s^2

Where,

s = 11.6 yd

Plug in the value of s

Area of the square = 11.6^2 = 134.6 $ yd^2

b. The shape given is a circle.

Area of the circle = \pi r^2

  • Where,

r = 12 cm

  • Plug in the value of r

Area of the square = \pi \times 12^2 = 452.2 $ cm^2

c. The shape given is a parallelogram.

Area of the parallelogram = bh

  • Where,

b = 7 cm

h = 5.8 cm

  • Plug in the value of b and h

Area of the parallelogram = 7 \times 5.8 = 40.6 $ cm^2

d. The shape given is a rectangle.

Area of the rectangle = l \times w

  • Where,

l = 8.3 ft

w = 5.2 ft

  • Plug in the value of l and w

Area of the rectangle = 8.3 \times 5.2 = 43.2 $ ft^2

e. The shape given is a trapezium.

Area of the trapezium = \frac{1}{2} (a + b)  \times h

  • Where,

a = 2.8 m

b = 10.4 m

h = 3.9 m

  • Plug in the value of a, b, and h

Area of the trapezium = \frac{1}{2}(2.8 + 10.4) \times 3.9 = 25.7 $ m^2

f. The shape given is a triangle. <em>(See attachment for the shape).</em>

Area of the triangle = \frac{1}{2}  \times b  \times h

  • Where,

b = 9 ft

h = 4.8 ft

  • Plug in the value of b, and h

Area of the triangle = \frac{1}{2} \times 9 \times 4.8 = 21.6 $ ft^2

Therefore, applying the formula for each identified shape that are given, the correct areas to each shape are:

a. <em>Square </em>= 134.6 sq. yd

b. <em>Circle </em>= 452.2 sq. cm

c. <em>Parallelogram </em>= 40.6 sq. cm

d. <em>Rectangle </em>= 43.2 sq. ft

e. <em>Trapezium </em>= 25.7 sq. m

f. <em>Triangle</em> = 21.6 sq. ft

Learn more here:

brainly.com/question/22560863

5 0
2 years ago
Bill is able to save $35/week after working part-time and paying his expenses. These two formulas show his weekly savings: f(1)
Umnica [9.8K]
1. We use the recursive formula to make the table of values:
f(1) = 35
f(2) = f(1) + f(2-1) = f(1) + f(1) = 35 + 35 = 70
f(3) = f(1) + f(3-1) = f(1) + f(2) = 35 + 70 = 105
f(4) = f(1) + f(4-1) = f(1) + f(3) = 35 + 105 = 140
f(5) = f(1) + f(5-1) = f(1) + f(4) = 35 + 140 = 175

2. We observe that the pattern is that for each increase of n by 1, the value of f(n) increases by 35. The explicit equation would be that f(n) = 35n. This fits with the description that Bill saves up $35 each week, thus meaning that he adds $35 to the previous week's value.

3. Therefore, the value of f(40) = 35*40 = 1400. This is easier than having to calculate each value from f(1) up to f(39) individually. The answer of 1400 means that Bill will have saved up $1400 after 40 weeks.

4. For the sequence of 5, 6, 8, 11, 15, 20, 26, 33, 41...
The first-order differences between each pair of terms is: 1, 2, 3, 4, 5, 6, 7, 8...since these differences form a linear equation, this sequence can be expressed as a quadratic equation. Since quadratics are functions (they do not have repeating values of the x-coordinate), therefore, this sequence can also be considered a function.
4 0
3 years ago
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