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solmaris [256]
2 years ago
15

Which surveys would a sample be appropriate for? Mark all that apply.

Mathematics
2 answers:
Sauron [17]2 years ago
4 0

Answer:

its A and D

Step-by-step explanation:

i just took the quiz :)

NNADVOKAT [17]2 years ago
4 0

Answer:

Helen & Kevin

Step-by-step explanation:

i got it right

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SOLUTION We observe that f '(x) = -1 / (1 + x2) and find the required series by integrating the power series for -1 / (1 + x2).
Ann [662]

Answer:

Required series is:

\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....

Step-by-step explanation:

Given that

                           f'(x) = -\frac{1}{1 + x^{2}} ---(1)

We know that:

                  \frac{d}{dx}(tan^{-1}x)=\frac{1}{1+x^{2}} ---(2)

Comparing (1) and (2)

                           f'(x)=-(tan^{-1}x) ---- (3)

Using power series expansion for tan^{-1}x

f'(x)=-tan^{-1}x=-\int {\frac{1}{1+x^{2}} \, dx

= -\int{ \sum\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx

= -\sum{ \int\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx

=-[c+\sum\limits^{ \infty}_{n=0} (-1)^{n}\frac{x^{2n+1}}{2n+1}]

=C+\sum\limits^{ \infty}_{n=0} (-1)^{n+1}\frac{x^{2n+1}}{2n+1}

=C-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....

as

                 tan^{-1}(0)=0 \implies C=0

Hence,

\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....

7 0
3 years ago
ANSWERR ASAPP!!! I GIVE BRAINLIESTT!!<br><br>Answer b and correct c and a if wrong ​
FrozenT [24]

Answer:

b is (4,55). c is correct I believe.

Step-by-step explanation:

You need to find where the lines cross on the graph. You see that at point (4,55)

6 0
2 years ago
Read 2 more answers
Please help me out with this question please!!!
bixtya [17]

Answer:

3 days

Step-by-step explanation:

company A would have the equation 50x+40 =y  and company B would be 30x + 100 =y. we're tying to find the days that these cost the same so you would do 50x+40 = 30+100. When you isolate x you get 3

7 0
2 years ago
The graph shown below expresses a radical function that can be written in the form f(x)= a(x + k)^1/n +C. What does the graph te
MAXImum [283]

Answer:

  C.  <em>c</em> is less than zero

Step-by-step explanation:

The parent radical function y=x^(1/n) has its point of inflection at the origin. The graph shows that point of inflection has been translated left and down.

<h3>Function transformation</h3>

The transformation of the parent function y=x^(1/n) into the function ...

  f(x) = a(x +k)^(1/n) +c

represents the following transformations:

  • vertical scaling by a factor of 'a'
  • left shift by k units
  • up shift by c units

<h3>Application</h3>

The location of the inflection point at (-3, -4) indicates it has been shifted left 3 units, and down 4 units. In the transformed function equation, this means ...

  • k = 3
  • c = -4

The graph says the value of c is less than zero.

__

<em>Additional comment</em>

Apparently, the value of 'a' is 2, and the value of n is 3. The equation of the graph seems to be ...

  f(x) = 2(x +3)^(1/3) -4

8 0
1 year ago
Write y=10x as a logarithmic function please
Margaret [11]
\bf \textit{exponential form of a logarithm}&#10;\\\\&#10;log_a  b=y \implies   a^y=  b\qquad\qquad &#10;%  exponential notation 2nd form&#10;a^y=  b\implies log_a  b=y \\\\&#10;-------------------------------\\\\&#10;y=10^x\implies log_{10}(y)=x
5 0
3 years ago
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