I believe the correct answer is true. <span>When solving a system of linear equations, try to algebraically form one equation that has only one variable. In this way, you can solve the value of that variable and eventually solve the other variables. Hope this answers the question. Have a nice day.</span>
Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)
so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288
so r = 5 and 3O = 288 + 360p and O = 96 + 120p
so one cube root is 5 (cos 96 + i sin 96)
Im a little rusty at this stuff Its been a long time.
Im not sure of the other 2 roots
sorry cant help you any more
Answer:
Option A - 
Step-by-step explanation:
We have given the expression 
We have to find the value of the expression ?
Solution :
Step 1 - Write the expression
Step 2 - Applying symbol rule i.e. multiplication of positive into negative is always negative, 
Step 3 - Solve
Therefore, The value of the expression is
So, Option A is correct.
Answer:
I think it's A.
hope this helps
have a good day :)
Step-by-step explanation:
A. x= 11/5
b. x= 6
c. x= -12/2
d. x= 6/5
