The ratio of the number of students to the number of teachers in a school is 17:5. If there are 35 teachers in a school, how man
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Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Up
Vertex: <span>(−<span>5/8</span>,−<span>41/16</span>)</span>
Focus: <span>(−<span>5/8</span>,−<span>5/2</span>)</span>
Axis of Symmetry: <span>x=−<span>5/8</span></span>
Directrix: <span>y=−<span>21/8</span></span><span><span> x. y
</span><span><span>−3. </span>20
</span><span><span>−2. </span>5
</span><span><span>−<span>5/8. </span></span><span>−<span>41/16
</span></span></span><span> 0. <span>−1
</span></span><span>1. <span>8
</span></span></span>
Direction: Opens Up
Vertex: <span>(−<span>5/8</span>,−<span>41/16</span>)</span>
Focus: <span>(−<span>5/8</span>,−<span>5/2</span>)</span>
Axis of Symmetry: <span>x=−<span>5/8</span></span>
Directrix: <span>y=−<span>21/8</span></span><span><span> x. y
</span><span><span>−3. </span>20
</span><span><span>−2. </span>5
</span><span><span>−<span>5/8. </span></span><span>−<span>41/16
</span></span></span><span> 0. <span>−1
</span></span><span>1. <span>8
</span></span></span>
Answer:
A 180° rotation of then a dilation by a scale factor of one-third
Step-by-step explanation:
The coordinates of the vertices of ΔABC are;
A(-9, 3), B(-9, 6), and C(0, 3)
The coordinates of the vertices of ΔA'B'C' are;
A'(3, -1), B'(3, -2), and C'(0, -1)
We note that for a 180° rotation transformation about the origin, we get;
Coordinates of preimage = (x, y)
Coordinates of image after 180° rotation about the origin = (-x, -y)
Therefore, a 180° rotation of ΔABC about the origin, would give ΔA''B''C'' as follows;
A(-9, 3), B(-9, 6), and C(0, 3) = A''(9, -3), B''(9, -6), and C''(0, -3)
The formula for a dilation of a point about the origin is given as follows;
Where;
k =The scale factor = 1/3, (one-third) we have;
A dilation of ΔA''B''C'', by a scale factor of 1/3, we get ΔA'B'C' as follows;
The coordinates of the vertices of ΔA'B'C' are A'(3, -1), B'(3, -2), and C'(0, -1), which is the same as the required coordinates of the image;
Therefore, the transformation that can be performed to show that ΔABC and ΔA'B'C' are similar are rotating ΔABC by 180° then a dilating the image derived after rotation by a scale factor of one-third (1/3) we get ΔA'B'C'.