Answer:
n + 4
Step-by-step explanation:
It´s like a normal sum, but since the number is unknown just put n.
This is a strange question, and f(x) may not even exist. Why do I say that? Well..
[1] We know that f(a+b) = f(a) + f(b). Therefore, f(0+0) = f(0) + f(0). In other words, f(0) = f(0) + f(0). Subtracting, we see, f(0) - f(0) = f(0) or 0 = f(0).
[2] So, what's the problem? We found the answer, f(0) = 0, right? Maybe, but the second rule says that f(x) is always positive. However, f(0) = 0 is not positive!
Since there is a contradiction, we must either conclude that the single value f(0) does not exist, or that the entire function f(x) does not exist.
To fix this, we could instead say that "f(x) is always nonnegative" and then we would be safe.
Answer:
348m
Step-by-step explanation:
I took the k12 test
Answer:
$63
Step-by-step explanation:
let x represent Charity B then Charity A = 5x
Sum the two and equate to 378, that is
x + 5x = 378
6x = 378 ( divide both sides by 6 )
x = 63
Thus Charity B received $63
