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Leviafan [203]
3 years ago
8

What is the molarity of a solution that contains 4.87 g KCI (74.55 g/mol) dissolved in in 500.0 ml water?

Chemistry
2 answers:
lbvjy [14]3 years ago
8 0

Answer:

Molarity = 0.13M

Explanation:

n=m/M = 4.87/74.55= 0.065mol, V= 500ml= 0.5dm3

Applying

n= C×V

0.065= C×0.5

C= 0.13M

Nuetrik [128]3 years ago
3 0

Answer:

It is the first answer choice

Explanation:

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3 years ago
Why is this considered a theory instead of a hypothesis or a law?
UNO [17]

Answer:

This is considered a hypothesis because it hasn't been confirmed. It is just a guess.

Explanation:

A hypothesis is a limited explanation of a phenomenon; a scientific theory is an in-depth explanation of the observed phenomenon. Law is a statement about an observed phenomenon or a unifying concept, according to Kennesaw State University. However, Newton's law doesn't explain what gravity is, or how it works.

3 0
3 years ago
How many liters of laughing gas are in 0.98 moles stp
Alex73 [517]

By applying ideal gas equation,

[tex]P\times V=n\times R\times T[\tex]

Where, P= pressure of gas

V=volume of gas

R=Gas constant

n=Number of moles of gas

T=Temperature

At STP, each gas has a defined value of pressure, volume and temperature.

P= 1 atm

R=0.0821 L atm mol⁻¹ K⁻¹

T= 0°C or 273 K

Putting all the values in the equation will give:

[tex]1\times V=0.98\times 0.0821\times 273[\tex]

V = 22 L

So the answer is 22 L.

4 0
4 years ago
Read 2 more answers
Round the following to three significant figures. a 17.5555 km 16 b. 1.0007 c.23.34271d. 99.991
julsineya [31]
A) 176 b)1.00 c)23.3 d)100
4 0
4 years ago
For the simple decomposition reactionAB(g)→ A(g) + B(g)Rate =k[AB]2 and k=0.2 L/mol*s . How long will it takefor [AB] to reach 1
mixer [17]

Answer:

6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.

Explanation:

Rate = k[AB]^2

The order of the reaction is 2.

Integrated rate law for second order kinetic is:

\frac{1}{[A_t]} = \frac{1}{[A]_0}+kt

Where, [A_0] is the initial concentration  = 1.50 mol/L

[A_t] is the final concentration  = 1/3 of initial concentration = \frac{1}{3}\times 1.50\ mol/L = 0.5 mol/L

Rate constant, k = 0.2 L/mol*s

Applying in the above equation as:-

\frac{1}{0.5} = \frac{1}{1.50}+0.2t

\frac{1}{1.5}+0.2x=\frac{1}{0.5}

t = 6.66\ s

<u>6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.</u>

5 0
3 years ago
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