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3 years ago

Round the following to three significant figures. a 17.5555 km 16 b. 1.0007 c.23.34271d. 99.991

Chemistry

1 answer:

julsineya [31]3 years ago

4 0

A) 176 b)1.00 c)23.3 d)100

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Cho biết độ tan của NH4Cl trong nước ở 20oC và 70oC lần lượt là 37,2 g/100 gam nước và 60,2 gam/100 g nước. Hòa tan 166,8 gam NH

Stolb23 [73]

Answer: Hợp chất CTHH 0 °C 10 °C 20 °C 30 °C 40 °C 50 °C 70 °C

Actini(III) hydroxide Ac(OH)3 0,0022

Amonia NH3 1176 900 702 565 428 333 188

Amoni azua NH4N3 16 25,3 37,1

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8 0

2 years ago

A dilute solution of bromine in carbon tetrachloride behaves as an ideal-dilute solution. The vapour pressure of pure CCl4 is 33

ANEK [815]

Explanation:

The given data is as follows.

Vapour pressure of pure $CCl_{4}$ = 33.85 Torr

Temperature = 298 K

Mole fraction of $Br_{2}$ = 122.36 torr

Therefore, calculate the vapor pressure of $Br_{2}$ as follows.

Vapour pressure of $Br_{2}$ = mole fraction of $Br_{2}$ x K of $Br_{2}$

= 0.050 x 122.36 Torr

= 6.118 Torr

So, vapor pressure of $Br_{2}$ is 6.118 Torr .

Now, calculate the vapor pressure of carbon tetrachloride as follows.

Vapour pressure of $CCl_{4}$ = mole fraction of $CCl_{4}$ x Pressure of $CCl_{4}$

= (1 - 0.050) × 33.85 Torr

= 32.1575 Torr

So, vapor pressure of $CCl_{4}$ is 32.1575 Torr .

Hence, the total pressure will be as follows.

= 6.118 Torr + 32.1575 Torr

= 38.2755 Torr

Therefore, composition of $CCl_{4}$ = $\frac{32.1575 Torr}{38.2755 Torr}$

= 0.8405

Composition of $CCl_{4}$ is 0.8405 .

And, composition of $Br_{2}$ = $\frac{6.118 Torr}{38.2755 Torr}$

= 0.1598

Composition of $Br_{2}$ is 0.1598 .

6 0

3 years ago

Which ones are right to this question?

Vitek1552 [10]

The average Kenectic energy

7 0

3 years ago

Convert 65.4 m to mm.<br> Helppp please

Ostrovityanka [42]

Answer:65.4 meters= 65400 millimeters

5 0

2 years ago

Read 2 more answers

List the protons, neutrons, and electrons for Ge2+<br> Please hurry

Nady [450]

Answer:

32, 30 and 41

Explanation:

The problem here is to find the number of:

Protons, neutrons and electrons in Ge²⁺

In this ion,

We must understand that for a net positive charge to remain on an atom, the number of protons must be greater than the number of electrons.

Ge is Germanium with atomic number of 32;

So the number of protons is 32

Since the atom has lost two electrons;

Number of electrons now is 32 - 2 = 30

Number of neutrons is 41 from the periodic table.

7 0

2 years ago