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harina [27]
4 years ago
10

How many liters of laughing gas are in 0.98 moles stp

Chemistry
2 answers:
Alex73 [517]4 years ago
4 0

By applying ideal gas equation,

[tex]P\times V=n\times R\times T[\tex]

Where, P= pressure of gas

V=volume of gas

R=Gas constant

n=Number of moles of gas

T=Temperature

At STP, each gas has a defined value of pressure, volume and temperature.

P= 1 atm

R=0.0821 L atm mol⁻¹ K⁻¹

T= 0°C or 273 K

Putting all the values in the equation will give:

[tex]1\times V=0.98\times 0.0821\times 273[\tex]

V = 22 L

So the answer is 22 L.

mariarad [96]4 years ago
4 0

3H2   +   N2 ===>   2NH3

GIVEN: 44.8 L of H2 at STP.

answer: mols of N2.

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40.32 kg NaHCO3
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In 40.32 kg of NaHCO₃, there are 2.890 × 10²⁶ formula units of NaHCO₃.

<h3>What is a formula unit?</h3>

A formula unit is the empirical formula of any ionic or covalent network solid compound used as an independent entity for stoichiometric calculations.

  • Step 1: Convert 40.32 kg to g.

We will use the conversion factor 1 kg = 1000 g.

40.32 kg × (1000 g/1 kg) = 4.032 × 10⁴ g

  • Step 2: Convert 4.032 × 10⁴ g to moles.

We will use the molar mass of NaHCO₃ as the conversion factor.

4.032 × 10⁴ g × (1 mol/84.01 g) = 479.9 mol

  • Step 3: Convert 479.9 moles to formula units (fu).

We will use Avogadro's number as the conversion factor.

479.9 mol × (6.022 × 10²³ fu/1 mol) = 2.890 × 10²⁶ fu

In 40.32 kg of NaHCO₃, there are 2.890 × 10²⁶ formula units of NaHCO₃.

Learn more about formula units here: brainly.com/question/2165878

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