Let f f and g g be functions such that f(0)=7,g(0)=5, f(0)=7,g(0)=5, f ′ (0)=8, g ′ (0)=6. f′(0)=8,g′(0)=6. Find h ′ (0) h′(0) f
1 answer:
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One way is to just expand it by using binomial theorem
or to use pascal's triangle
ok so
to find the nth term of a binomial, (a-b). where the binomial is to the r power you do
n-1=k
rCk times
and rCk=
so
4th term
4-1=3
6 is exponent
6C3
=
=
=
the 4th term is
or to use pascal's triangle
ok so
to find the nth term of a binomial, (a-b). where the binomial is to the r power you do
n-1=k
rCk times
and rCk=
so
4th term
4-1=3
6 is exponent
6C3
the 4th term is
Answer:
B
Step-by-step explanation:
Using the identities
sec x = , csc x =
, cot x =
, then
sec²x cot²x
= ×
( cancel out cos²x )
=
= csc²x → B