Answer:
His collection increased in a 20%.
Step-by-step explanation:
If 100% represents 10 records, what percentage would be for 12 records?
x = 12 100% / 10 = 120%
So, if we subtract 120% - 100%, it's gonna result in a difference of 20%, which means that 12 represents a 20% more, or his collection increased in a 20%.
Initially, Alice had 28 sweets and Olivia 12 sweets.
Step-by-step explanation:
First assume that Aunty Joan has x number sweets.
Alice and Olivia shared the x sweets in a ration of 7:3, this means
Alice had 7/10 x sweets and Olivia had 3/10 sweets.
Alice gives 3 sweets to Olivia, Alice will remain with ;
Then the new ratio changes to 5:3 which means Alice will have 5/8 x number of sweets.
Equate the number of sweets for Alice in the two cases, which is
So there were 40 sweets at first
Using the ratio of 7:3 then
Alice had 7/10 *40 = 28 sweets
Olivia had 3/10*40= 12 sweets
Alice gave Olivia 3 sweets, so she will remain with 28-3 =25 sweets. Olivia will now have 15 sweets.The new ratio will be 25:15 simplified as 5:3.
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Ratio : brainly.com/question/11095585
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These are just a few of the things you will learn in 6th grade. You will learn how to write a two- variable equation, how to identify the graph of an equation, graphing two-variable equations. how to interpret a graph and a word problem, and how to write an equation from a graph using a table, two-dimensional figures,Identify and classify polygons, Measure and classify angles,Estimate angle measurements, Classify triangles, Identify trapezoids, Classify quadrilaterals, Graph triangles and quadrilaterals, Find missing angles in triangles, and a lot more subjects. <span><span><span>Find missing angles in quadrilaterals
</span><span>Sums of angles in polygons
</span><span>Lines, line segments, and rays
</span><span>Name angles
</span><span>Complementary and supplementary angles
</span><span>Transversal of parallel lines
</span><span>Find lengths and measures of bisected line segments and angles
</span><span>Parts of a circle
</span><span>Central angles of circles</span></span>Symmetry and transformations
<span><span>Symmetry
</span><span>Reflection, rotation, and translation
</span><span>Translations: graph the image
</span><span>Reflections: graph the image
</span><span>Rotations: graph the image
</span><span>Similar and congruent figures
</span><span>Find side lengths of similar figures</span></span>Three-dimensional figures
<span><span>Identify polyhedra
</span><span>Which figure is being described
</span><span>Nets of three-dimensional figures
</span><span>Front, side, and top view</span></span>Geometric measurement
<span><span>Perimeter
</span><span>Area of rectangles and squares
</span><span>Area of triangles
</span><span>Area of parallelograms and trapezoids
</span><span>Area of quadrilaterals
</span><span>Area of compound figures
</span><span>Area between two rectangles
</span><span>Area between two triangles
</span><span>Rectangles: relationship between perimeter and area
</span><span>compare area and perimeter of two figures
</span><span>Circles: calculate area, circumference, radius, and diameter
</span><span>Circles: word problems
</span><span>Area between two circles
</span><span>Volume of cubes and rectangular prisms
</span><span>Surface area of cubes and rectangular prisms
</span><span>Volume and surface area of triangular prisms
</span><span>Volume and surface area of cylinders
</span><span>Relate volume and surface area
</span><span>Semicircles: calculate area, perimeter, radius, and diameter
</span><span>Quarter circles: calculate area, perimeter, and radius
</span><span>Area of compound figures with triangles, semicircles, and quarter circles</span></span>Data and graphs
<span><span>Interpret pictographs
</span><span>Create pictographs
</span><span>Interpret line plots
</span><span>Create line plots
</span><span>Create and interpret line plots with fractions
</span><span>Create frequency tables
</span><span>Interpret bar graphs
</span><span>Create bar graphs
</span><span>Interpret double bar graphs</span><span>
</span></span><span>
</span></span>
The formula for density of an object is Density=
First you plug in the information you already know. 163.5=
Now you have to solve for the mass so you multiply 0.492 by 163.5
Lastly, you simplify and you will get 80.44. Hope this helped :)
14-6 over 3--2
8/5
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