Answer:
since the lengths are consecutive odd numbers and the perimeter of the triangle is 51cms. Let x be the unknown length.
so 3x=51 ; x=17 . now the sides can be 15cms, 17cms, 19cms.
check Add them up it is 51cms which is the perimeter and the consecutive odd numbers
Answer:
Step-by-step explanation:
Apply the Pythagorean Theorrem. Find the sum of the squares of the two shortest sides and determine whether this sum equals the square of the longest side:
#19: 5^2 + 12^2 = ? = 13^2
25 + 144 = ? = 169 This is true, so you do have a right triange in #19.
#21: 2^2 + 4^2 = ? = 7^2, or 4 + 16 = ? = 49 This is false. Not a right
triangle.
Apply this same approach (Pythagorean Theorem) to the remaining problems.
2/2 part of the equation is ≤ B
maybe 30/100 ≤ B
Answer:
Step-by-step explanation:
If this is in terms of angles, 4x+6 must be equal to 90 since it is half of the angle produced by a line (180°) So solving for 4x+6=90, x=21
Equation 1: y = -2x + 1
Equation 2: y = 2x - 3
Since both equations already have y isolated, we are able to simply set the right side of both equations equal to each other. Since we know that the value of y must be the same, we can do this.
-2x + 1 = 2x - 3
1 = 4x - 3
4 = 4x
x = 1
Then, we need to plug our value of x back into either of the original two equations and solve for y. I will be plugging x back into equation 2 above.
y = 2x - 3
y = 2(1) - 3
y = 2 - 3
y = -1
Hope this helps!! :)
