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3 years ago

Solve this inequality : 5x+7x<36

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

7 0

Answer:

x < 3

Step-by-step explanation:

5x+7x<36

12x<36

Divide both sides by 12

x<3

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Roberto and Jeanne played a difficult computer game. Roberto's finalas -60 points, and Jeanne's final score was -160 points. Use

Aleksandr-060686 [28]

Answer: -60 > -160

Roberto has the higher final score.

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

-60 is greater than -160, because -60 is father to the right than -160 on the number line (see attachment)

Since the direction of < and > always points towards the smallest number.

-60 > -160

Roberto has the higher final score.

Feel free to ask for more if needed or if you did not understand something.

6 0

4 years ago

Can somebody help me?

nikklg [1K]

Answer:

8a + 16c

(8 ×-5 ) +(16 × -1)

-40 +(-16)

-56

7 0

3 years ago

1/3(y - 2) -5/6 (y + 1) =3/4 (y - 3) - 2

Nataly [62]

Answer:

$y=\frac{11}{5}$

Step-by-step explanation:

Given expression

$\frac{1}{3}(y-2)-\frac{5}{6}(y+1)=\frac{3}{4}(y-3)-2$

To solve for $y$ for the given expression.

Solution:

We multiply each term with the least common multiple of the denominators of the fraction in order to remove fractions.

The multiples of the denominators are:

3 = 3,6,9,12,15

6 = 6,12

4 = 4,8,12

The least common multiple = 12.

Multiplying each term with 12.

$12.\frac{1}{3}(y-2)-12.\frac{5}{6}(y+1)=12.\frac{3}{4}(y-3)-2(12)$

$4(y-2)-10(y+1)=9(y-3)-24$

Using distribution.

$4y-8-10y-10=9y-27-24$

Simplifying.

$-6y-18=9y-51$

Adding $6y$ both sides.

$-6y+6y-18=9y+6y-51$

$-18=15y-51$

Adding 51 both sides.

$-18+51=15y-51+51$

$33=15y$

Dividing both sides by 15.

$\frac{33}{15}=\frac{15y}{15}$

$\frac{33}{15}=y$

Simplifying fractions.

$\frac{11}{5}=y$

∴ $y=\frac{11}{5}$ (Answer)

7 0

3 years ago

Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ

Deffense [45]

Answer:

$\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}$

Step-by-step explanation:

$Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}$

$\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16$

$\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i$

6 0

3 years ago

Read 2 more answers

1 point

Kamila [148]

Answer:

angle 3 = 27 degrees

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers